How to much mass does it take to change Neptune's Orbit?

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SUMMARY

To change Neptune's orbit from a circular path at 22 AU to 30 AU, it must scatter a specific mass of celestial bodies to Jupiter. The discussion establishes that the energy lost by Neptune when scattering these bodies is derived from their semimajor axis, averaging 15.5 AU. The calculations indicate that the mass of Neptune is equal to the sum of the remaining mass and the mass captured by Jupiter, leading to a system of two linear equations that can be solved to find the required mass for the orbital change.

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Every time Neptune scatters bodies to Jupiter, Neptune gains energy and its
orbit becomes larger. How much mass would Neptune have to scatter to Jupiter
for Neptune’s orbit to have changed from a circular orbit at 22AU to a circular
orbit at 30AU? Give the answer in terms of Neptune’s mass and assume that all
scattered objects approached Neptune on circular orbits but left on orbits with
aphelia of 26AU (average between 22 and 30) and perihelia of 5 AU.
 
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masterpiece5 said:
Every time Neptune scatters bodies...

...aphelia of 26AU (average between 22 and 30) and perihelia of 5 AU.
Hello masterpiece5

The energy of bodies is given by the semimajor axis. Which is here 15,5. I suppose you mean that Jupiter captures them when they are near to the perihelium of 5 AE?

The lost masses go from somewhere in between 22..30 AU to 15,5 AU that is the energy Neptune loses when the bodies are captured by Jupiter, variing form 2/3 to 1/2 of the original energy. Mean of 2/3 and 1/2 is 7/12.

On the other hand gain of the remaining Neptune has to be: 30/22=15/11

Mass of Neptune = Mass_remaining + Mass_captured

Total energy = 15*Mass_remaining/11 +7*Mass_captured/12

Two linear equations with two unknowns must be solvable.

By the way greetings to this site

Janm
 

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