A How to observe difference of L/R rotation intensity of CPL

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Chiral circularly polarized luminescent materials have been developed, showing a luminescence asymmetry factor (g lum) around 10^-1. Despite this, the intensity difference between left and right-handed circularly polarized light is not perceivable to the naked eye under polarizers. Suggestions include using optical filters or enhancing excitation to make the difference more intuitive. One proposed method is to chop between the two light sources at about 1Hz to potentially reveal the 10% intensity difference. This approach may help in visually detecting the subtle variations in light intensity.
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How to observe the difference between left and right rotation intensity of chiral circularly polarized light
I have prepared chiral circularly polarized luminescent materials based on liquid crystal. The luminescence asymmetry factor(g lum) measured by the circular polarization spectrometer is in the order of 10^-1. However, the difference in light intensity cannot be viewed by the naked eyes under the left/right-handed polarizer. Is there any way to directly observe the difference of left- and right-handed circularly polarized light intuitively (for examples, using designed optical filter or enhance the excitation)?
 
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AFAIK, almost all solid-state optical detectors can measure a 10% difference in intensity really easily.
 
dhqzd said:
However, the difference in light intensity cannot be viewed by the naked eyes under the left/right-handed polarizer.
Can you chop between the two different sources to see if your eye can then detect the 10% difference? You could chop at about 1Hz or so at first, and then try faster if that makes the difference more obvious.
 
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