MHB How to Perform Implicit Differentiation on \(x^2-4xy+y^2=4\)?

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To perform implicit differentiation on the equation \(x^2 - 4xy + y^2 = 4\), the derivative \(dy/dx\) is derived by applying the product rule and isolating \(y'\). The differentiation leads to the equation \(y'(-4x + 2y) = -2x + 4y\). After isolating \(y'\), the final expression is \(y' = \frac{-x + 2y}{-2x + y}\). There is a mention of a potential typo regarding the factoring of 4, but the calculations are confirmed to be correct. The discussion emphasizes the importance of careful differentiation and isolation of variables in implicit differentiation.
karush
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$\tiny{166.2.6.5}$
Find y'
$$x^2-4xy+y^2=4$$
dy/dx
$$2x-4(y+xy')+2yy'=2x-4y-4xy'+2yy'=0$$
factor
$$y'(-4x+2y)=-2x+4y=$$
isolate
$$y'=\dfrac{-2x+4y}{-4x+2y}
=\dfrac{-x+2y}{-2x+y}$$

typo maybe not sure if sure if factoring out 4 helped
 
Last edited:
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karush said:
$\tiny{166.2.6.5}$
Find y'
$$x^2-4xy+y^2=4$$
dy/dx
$$2x-4(y+xy')+2yy'=2x-4y-4xy'+2yy'=0$$
factor
$$y'(-4x+2y)=-2x+4y=$$
isolate
$$y'=\dfrac{-2x+4y}{-4x+2y}
=\dfrac{-x+2y}{-2x+y}$

typo maybe not sure if sure if factoring out 4 helped

What you've done is correct.
 
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