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Albert said:
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let area of $\triangle 1=$ area of $\triangle 2=t$
and area of $\triangle 3=1$
then area of $\triangle 4=t^2$
we have area of $\triangle 3 +$ area of $ \triangle 4=t^2+1 \geq$ area of $\triangle 1+$ area of $\triangle 2=2t$
$(AP\geq GP)$
 
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