How to Prove Galois Extension Statements in a Normal and Separable Field?

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Discussion Overview

The discussion revolves around proving statements related to Galois extensions in the context of field theory. Participants explore implications of the normal and separable properties of Galois extensions, focusing on the relationships between fixed fields and Galois groups.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant seeks hints to prove that if \( F \leq K \leq E \), then \( \mathcal{F}(\mathcal{G}(E/K)) \geq K \) and if \( H \leq \mathcal{G}(E/F) \), then \( \mathcal{G}(E/\mathcal{F}(H)) \geq H \).
  • Another participant provides a proof outline for the first statement by showing that any element \( x \in K \) is fixed by the Galois group \( \mathcal{G}(E/K) \), thus belonging to the fixed field \( \mathcal{F}(\mathcal{G}(E/K)) \).
  • For the second statement, the same participant argues that elements of \( H \) fix elements in \( \mathcal{F}(H) \), leading to the conclusion that \( H \) is contained in \( \mathcal{G}(E/\mathcal{F}(H)) \).
  • Another participant proposes additional statements regarding the relationships between Galois groups and fixed fields when considering nested extensions \( F \leq K_1 \leq K_2 \leq E \) and subgroups \( H_1 \leq H_2 \leq \mathcal{G}(E/F) \).
  • This participant outlines proofs for both additional statements, showing that the properties of Galois groups and fixed fields hold under these conditions.
  • One participant expresses satisfaction with the proofs provided and inquires about potential improvements.

Areas of Agreement / Disagreement

Participants generally agree on the validity of the proofs presented for the statements discussed, although there is an ongoing inquiry into possible improvements and clarifications.

Contextual Notes

The discussion assumes familiarity with the definitions and properties of Galois extensions, fixed fields, and Galois groups, which may not be explicitly detailed in the posts.

mathmari
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Hey! :o

Let $E/F$ be a Galois extension. I want to show the following:
  1. $F\leq K\leq E \Rightarrow \mathcal{F}(\mathcal{G}(E/K))\geq K$
  2. $H\leq \mathcal{G}(E/F)\Rightarrow \mathcal{G}(E/\mathcal{F}(H))\geq H$

Since $E/F$ is a Galois extension, we have that the extension is normal and separable.

Could you give me some hints how we could show these statements? (Wondering)
 
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mathmari said:
Hey! :o

Let $E/F$ be a Galois extension. I want to show the following:
  1. $F\leq K\leq E \Rightarrow \mathcal{F}(\mathcal{G}(E/K))\geq K$
  2. $H\leq \mathcal{G}(E/F)\Rightarrow \mathcal{G}(E/\mathcal{F}(H))\geq H$

Since $E/F$ is a Galois extension, we have that the extension is normal and separable.

Could you give me some hints how we could show these statements? (Wondering)

Both statements follow easily from definitions.

(1). Let $x\in K$ be arbitrary. We will show that $x$ is in the fixed field of $\mathcal G(E:K)$. Pick $\sigma\in \mathcal G(E:K)$. Then $\sigma$ fixes $K$ point wise. Therefore $\sigma(x) = x$ and we have $x\in \mathcal F(\mathcal G(E:K))$.

(2). Let $h\in H$. Then $h$ fixes each element in $\mathcal F(H)$ (just by definition). Thus $h\in \mathcal G(E:\mathcal F(H))$ and we are done.
 
I understand! (Nerd) I want to show the following statements:
  • $F\leq K_1\leq K_2\leq E\Rightarrow \mathcal{G}(E/K_1)\geq \mathcal{G}(E/K_2)$
  • $H_1\leq H_2\leq \mathcal{G}(E/F)\Rightarrow \mathcal{F}(H_1)\geq \mathcal{F}(H_2)$

For the first one I have done the following:
Let $\sigma \in \mathcal{G}(E/K_2)$ then $\sigma (k_2)=k_2,\forall k_2\in K_2$. Since $K_1\leq K_2$ we have that this is true for all $k_1\in K_1$, so $\sigma (k_1)=k_1,\forall k_1\in K_1$, therefore, $\sigma \in \mathcal{G}(E/K_1)$.

For the second one I have done the following:
Let $f\in \mathcal{F}(H_2)$ then $\sigma (f)=f,\forall \sigma \in H_2$. Since $H_1\leq H_2$ , we get that $\sigma (f)=f \forall \sigma \in H_1$ too, and so $f\in F(H_1)$.

Is everything correct? Could I improve something? (Wondering)
 
mathmari said:
I understand! (Nerd) I want to show the following statements:
  • $F\leq K_1\leq K_2\leq E\Rightarrow \mathcal{G}(E/K_1)\geq \mathcal{G}(E/K_2)$
  • $H_1\leq H_2\leq \mathcal{G}(E/F)\Rightarrow \mathcal{F}(H_1)\geq \mathcal{F}(H_2)$

For the first one I have done the following:
Let $\sigma \in \mathcal{G}(E/K_2)$ then $\sigma (k_2)=k_2,\forall k_2\in K_2$. Since $K_1\leq K_2$ we have that this is true for all $k_1\in K_1$, so $\sigma (k_1)=k_1,\forall k_1\in K_1$, therefore, $\sigma \in \mathcal{G}(E/K_1)$.

For the second one I have done the following:
Let $f\in \mathcal{F}(H_2)$ then $\sigma (f)=f,\forall \sigma \in H_2$. Since $H_1\leq H_2$ , we get that $\sigma (f)=f \forall \sigma \in H_1$ too, and so $f\in F(H_1)$.

Is everything correct? Could I improve something? (Wondering)
This is fine.
 
Thank you very much! (Happy)
 

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