How to prove this congruent proof?

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SUMMARY

The discussion centers on proving the statement that if \( a \equiv b \mod n \) and \( a^{k-1} \equiv b^{k-1} \mod n \), then \( a^k \equiv b^k \mod n \) for \( n > 0 \) and \( k > 1 \). The proof by induction is suggested as a method to establish this congruence. The participants clarify the notation and emphasize the importance of understanding the rules for multiplication modulo \( n \) in the context of the proof.

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If a is congruent to b mod n and a^k−1 is congruent to b^k−1 mod n, then a^k is congruent to b^k mod n.? n>0 and k>1

How to prove it by induction?
 
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I'm assuming that's ak-1 and not ak-1. Do you know what the rules are for multiplication modulo n?
 

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