How to rig multiple IR2103 to form an H-bridge to excite transformer

  • Thread starter checkmatescott
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In summary, the OP is trying to design a machine that puts out a constant current, and wants to put it through an H-bridge setup to reverse the polarity at 50hz. After that, the 55v at 50hz will excite a transformer with a turn ratio of 4.182 to achieve an approximate 230v ac.
  • #1
checkmatescott
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TL;DR Summary
I need to know how to ocsillate the current between +55v and reverse. I have been advised to use multiple IR2103 half bridge drivers in conjunction with an arduino and 4 digital pins need the guidence to setup this circuit. Can anybody help. The more help I get the easier it is to understand the manual!
I am designing a machine that puts out constant ,and I want to put it through an H-bridge style setup to reverse the polarity at 50hz, by utilising IR2103 half-bridge's and arduino. after hat the 55v at 50hz will excite a transformer with turn ration 4.182 to achieve approximately 230v ac. thanks for any help in advance!
 
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  • #2
230 volts is a high and lethal voltage. If you cannot read and understand the manufacturer's datasheet, then you lack the experience and training necessary to safely implement the circuit.
 
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  • #3
Well then talk me through It, its not like im going to hold some guy on the internet accountable, for some help and advice he gave me. I just want to know how to oscillate 55v at 50hz! its for my project and btw i wear rubber gloves
 
  • #4
At the end of the day its a chip with 8 pins surely it cant be that hard to explain the operation. treat explaining to me as a challenge and don't think about the ethics ie "its too high of a voltage for him to handle or understand, it could be dangerous"
 
  • #5
For any help, I would be forever in your debt and will appreciate it a lot.
 
  • #6
Unless it's too difficult for you to explain.
 
  • #7
checkmatescott said:
... its not like im going to hold some guy on the internet accountable, ...
This website has rules, against dangerous activities, to protect this website.

I am not prepared to assist you in your attempt at gaining a Darwin Award.

Go to college and study. Train to qualify as an electrician or an engineer.

Find out why your other thread was paused.
 
  • #8
The part I need comes before the transformer and is therefore not dangerous
 
  • #9
I can see that you don't want to part with your knowledge. I understand the not gates and nor gates I don't know what UV means and I don't know what dead time means. I understand the pulse generation and how it works, I understand the internal transistors and I understand the pulse filter, so there's alot I do get. I just need some help I have a gcse in electronics and a level 3 diploma in electrical and mechanical engineering. and ok another approach can you tell me where I can get the information I need that explains how to get the desired ac at 50hz 50% duty cycle
 

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  • #10
checkmatescott said:
The part I need comes before the transformer and is therefore not dangerous
One thing leads to another.

You are clearly inexperienced, and are not in a position to assess the danger.
https://en.wikipedia.org/wiki/Dunning–Kruger_effect

Why do you not simulate the circuit with LTspice?

A transformer with a turns-ratio of 4.182 would have too many turns and too much resistance. 500 : 2091 = 4.182
 
  • #11
alternating 55v on a coil with 1:4.182 the output will be around 230v i need 55v ac 50hz 50% duty cycle. ok I will attempt to use LTSpice but i need the
 
  • #12
because 55 * 4.182 = 230.01
 
  • #13
ok so another approach can i just BUY an inverter that takes an input of 55v?
 
  • #14
There is still an elephant in the room.

How much current can you draw from the 55 volt supply before the voltage falls below 50 volts?

You need to know that before designing or buying an inverter.
 
  • #15
ok I next go to work on it for 2 hours on friday. I have two meters, my four coils are connected to a 10 diode bridge similar to this. I still need to do that check, I will be using two multi meters at the same time one measuring votage accross the output, and the other in-line with a power resistor of 27 ohm 100w to give current reading and I do realise that if I dont want to blow the power resistor i can only run it up to 50v because 50/27=1.185185 and then for power multiply current by voltage eg 1.185185*50 which equals to 92.approximatly, I think max I can do it 52v, but in reality when I tested for current, I was getting up to 70 amps, so yeah I need to the voltage check on one multimeter and current showing on the other at the same time, cheers
 

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  • #16
and ok say i find this time that the voltage drops from 55 to 50, then what procedure do I do to choose something adequit ? method?
 
  • #17
Baluncore said:
Find out why your other thread was paused.
@checkmatescott -- It is against the PF rules to try to reopen a locked thread. This thread here is also on pause. I will answer your PM about the first thread later today.
 
  • #18
berkeman said:
@checkmatescott -- It is against the PF rules to try to reopen a locked thread. This thread here is also on pause. I will answer your PM about the first thread later today.
After a long PM conversation, the OP will not be returning to PF. I mention why at the end of his original thread on these questions. Have a nice day.
 
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Related to How to rig multiple IR2103 to form an H-bridge to excite transformer

1. How do I connect multiple IR2103 drivers to form an H-bridge circuit?

To connect multiple IR2103 drivers to form an H-bridge, you will need four IR2103 drivers, one for each of the four switches in the H-bridge. Connect the high-side driver outputs (HO) to the gates of the high-side MOSFETs and the low-side driver outputs (LO) to the gates of the low-side MOSFETs. Ensure that the high-side floating supplies (VB) are connected to the source of the high-side MOSFETs and the low-side supplies (VCC) are connected to the ground. The inputs (HIN and LIN) of each IR2103 should be driven by the appropriate PWM signals to control the switching of the MOSFETs.

2. What power supply voltages are required for the IR2103 drivers in an H-bridge configuration?

The IR2103 drivers typically require a logic supply voltage (VCC) of 10-20V for the low-side driver and a floating supply voltage (VB) for the high-side driver, which is typically derived from a bootstrap capacitor. The bootstrap capacitor is charged from the VCC supply through a diode when the low-side MOSFET is on. The exact voltage requirements will depend on the specific MOSFETs used and the desired operating conditions.

3. How do I ensure the proper timing and synchronization of the IR2103 drivers in an H-bridge?

Proper timing and synchronization of the IR2103 drivers can be achieved by using a microcontroller or a dedicated PWM controller to generate the appropriate control signals. The control signals should be designed to ensure that the high-side and low-side MOSFETs on the same leg of the H-bridge are never on simultaneously, which would cause a short circuit. Dead-time insertion is crucial to prevent shoot-through and can be implemented in the control logic or by using external dead-time circuits.

4. How do I protect the H-bridge circuit from overcurrent and short-circuit conditions?

To protect the H-bridge circuit from overcurrent and short-circuit conditions, you can use current sensing resistors or Hall-effect current sensors to monitor the current flowing through the MOSFETs. If an overcurrent condition is detected, the control logic should immediately turn off the MOSFETs to prevent damage. Additionally, you can implement overcurrent protection features in the microcontroller or use dedicated protection ICs that provide fault detection and shutdown capabilities.

5. What are the key considerations for selecting MOSFETs to be used with IR2103 drivers in an H-bridge?

When selecting MOSFETs for use with IR2103 drivers in an H-

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