How to Set Undervoltage Lockout for TPS63001?

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SUMMARY

The discussion focuses on configuring the TPS63001 integrated circuit (IC) to implement an undervoltage lockout (UVLO) feature suitable for lithium-ion batteries. The default UVLO threshold of 1.8V is deemed too low, prompting the user to explore creating a voltage divider for the Vina pin to achieve a cutoff around 2.8V. Recommendations include testing the circuit in a lab setting and considering the impact of current leakage from the voltage divider, with a suggestion to use a potentiometer for fine-tuning the voltage levels.

PREREQUISITES
  • Understanding of TPS63001 datasheet specifications
  • Basic knowledge of voltage divider circuits
  • Familiarity with lithium-ion battery characteristics
  • Experience with PCB design and prototyping
NEXT STEPS
  • Research how to design voltage dividers for specific UVLO thresholds
  • Learn about the electrical characteristics of the TPS63001, focusing on the Vina pin
  • Explore methods to minimize current leakage in voltage divider circuits
  • Investigate the use of potentiometers in circuit design for adjustable parameters
USEFUL FOR

Electronics engineers, circuit designers, and hobbyists working with power management ICs, particularly those integrating lithium-ion batteries into their designs.

samski
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Hey, i am using one of these ICs to provide a 3.3V power supply from a li-ion battery. it works well but has an undervoltage lockout of 1.8v, much too low for a lithium ion battery.

here is the datasheet:
http://focus.ti.com/lit/ds/symlink/tps63000.pdf

now it says on the pin descriptions that Vina is the control stage supply... this is also the pin that the undervoltage lockout is measured from. so could i create a potential divider for this pin so that when the li-ion voltage drops to ~2.8V, the chip locks out? what should be the minimum input current for this pin? i can't find a value given in the electrical characteristics -there is a circuit on page 11 which uses a 100R to the vina and other pins. using this and a Vin cut off of 2.9, i calculated 61ohms for the paired resistor. but this gives 18ma current leak, a little high if the battery is left for any time... (its a 1Ah)

sorry if this is in wrong forum

thanks for any help

sam
 
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samski.

Rig up the circuit in your lab and find out the results.
The current shouldn't matter at that pin..
If its going into PCB then provide an option for voltage divider, and check it out
after you get the PCB
 
hmm i thought it might being the "power supply for control stage" ill stick a pot on it and ill also try one on EN...
 

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