How to Sketch the Function ƒ(x) = 1/√(k2-x2)?

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Homework Help Overview

The discussion revolves around the function ƒ(x) = 1/√(k² - x²), where k is a positive constant. Participants are tasked with sketching the graph of this function and determining its domain.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants express confusion regarding the parameter k, questioning its possible values and implications for the function. There are suggestions to visualize the graph of the related function √(k² - x²) to aid in understanding the reciprocal function.

Discussion Status

The discussion is ongoing, with participants exploring the implications of k as a parameter and how it affects the graph. Some guidance has been offered on sketching the graph, but no consensus has been reached on the domain or specific values for k.

Contextual Notes

Participants are navigating the constraints of the problem, particularly regarding the unspecified nature of k and its role in defining the function's behavior.

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Homework Statement


Consider the function ƒ:-k,k→R, where ƒ(x) = 1/√(k2-x2), where k is a positive constant.
(i) Sketch the graph of y = ƒ(x)
(ii) What is the domain of the function?

Homework Equations


ƒ(x) = 1/√(k2-x2)

The Attempt at a Solution


I don't understand how I am supposed to solve this. Couldn't k equal anything? Why couldn't it be 1 or 2? This makes no sense.
Help is appreciated. Thanks.
 
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noahsdev said:

Homework Statement


Consider the function ƒ:-k,k→R, where ƒ(x) = 1/√(k2-x2), where k is a positive constant.
(i) Sketch the graph of y = ƒ(x)
(ii) What is the domain of the function?

Homework Equations


ƒ(x) = 1/√(k2-x2)

The Attempt at a Solution


I don't understand how I am supposed to solve this. Couldn't k equal anything? Why couldn't it be 1 or 2? This makes no sense.
Help is appreciated. Thanks.
k is an unspecified constant - a parameter. k could be 1 or 2, but you shouldn't assume that it is any specific value.

Can you sketch the graph of y = ##\sqrt{k^2 - x^2}##? If you can get this graph, then the graph of f is just the reciprocal.
 
noahsdev said:
I don't understand how I am supposed to solve this. Couldn't k equal anything? Why couldn't it be 1 or 2? This makes no sense.
Help is appreciated. Thanks.

Just draw an x axis, mark some point on the positive side, and label it k. Then draw your graph.
 
LCKurtz said:
Just draw an x axis, mark some point on the positive side, and label it k. Then draw your graph.
noahsdev, after you label some point k on the positive side, label another as -k on the negative side. Then draw your graph.
 

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