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Well i know how to solve a simple equation with 2 incognites like:

x+y=2

x+4=2y

So in this case i do a substitue y=x-2 and use it in the second equation and it would be like:

x+4=2(x-2)

But the problem is if they only give me one equation with 2 incognites how can i solve it?

Example:

3x-4y+2=2(x+1)

Thanks!