How to Solve Complex Eigenvectors in Matrix Algebra

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When dealing with complex eigenvalues in an nxn matrix, the process involves computing the null space of A-lambdaI, but this can become complicated for n > 2. Gaussian elimination is often recommended, though it can be cumbersome, especially without computational tools. If substitution leads to trivial equations like 0 = 0, it indicates that the rows are dependent, and any row can be used to find a solution. Using a graphing calculator, such as a TI-93, can simplify the process of finding eigenvectors. Overall, leveraging technology can significantly ease the complexity of solving for eigenvectors in larger matrices.
tophman
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Hey,

I have a quick question that I can not seem to find much of an answer to in my text. When working with a nxn matrix, A, and you find eigenvalues that are complex, I'm confused about how to go about finding the actual eigenvector. I know we compute the null space of A-lambdaI, but that is where I seem to get stuck. For a 2x2, easy enough and I can do it. The problem is when n > 2. Gaussian elimination becomes a ridiculous mess. Is that the only way to do it? When I do substitution I end up with 0 = 0 which makes me think that each row is just some multiple of the other. If this is the case, do I just use any row I want?

Basically, I'm completely stuck with how to solve the complex matrix.

Any help would be greatly appreciated! :rolleyes:
 
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tophman said:
Hey,

I have a quick question that I can not seem to find much of an answer to in my text. When working with a nxn matrix, A, and you find eigenvalues that are complex, I'm confused about how to go about finding the actual eigenvector. I know we compute the null space of A-lambdaI, but that is where I seem to get stuck. For a 2x2, easy enough and I can do it. The problem is when n > 2. Gaussian elimination becomes a ridiculous mess. Is that the only way to do it? When I do substitution I end up with 0 = 0 which makes me think that each row is just some multiple of the other. If this is the case, do I just use any row I want?

Basically, I'm completely stuck with how to solve the complex matrix.

Any help would be greatly appreciated! :rolleyes:
Well, of course, you get "0= 0". In order to be an eigenvalue, the equations you get with \lambda equal to that eigenvalue, must be dependent so that 0 is not the only solution. I don't know what problem you are doing but Gaussian elimination is the best way to go- expect, of course, to use a TI-93 calculator that will do eigenvectors for you!
 
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