How to solve for average velocity on a distance time graph?

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SUMMARY

The average speed for the teacher's round trip can be calculated using the formula for average speed, which is the total distance divided by the total time. The teacher drives to work at an average velocity of 80 km/h and returns home at 120 km/h. Since the distance covered is the same both ways, the total distance is twice the one-way distance. The total time can be expressed in terms of that distance, leading to a definitive calculation of average speed for the entire trip.

PREREQUISITES
  • Understanding of average speed and velocity concepts
  • Basic knowledge of distance-time relationships
  • Familiarity with the formula for average speed
  • Ability to solve equations involving distance and time
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  • Study the formula for average speed in detail
  • Learn about instantaneous velocity and its applications
  • Explore distance-time graphs and their interpretations
  • Practice problems involving average speed calculations
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Students studying physics or mathematics, educators teaching kinematics, and anyone interested in understanding motion and speed calculations.

justinh8
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Homework Statement


Hi i need some help with this question: A teacher drives to work at a average velocity of 80km/h. He forgets the test and INSTANTLY turns around and travels back home at 120km/h. What is the average speed for the trip?
Do i have to find instantaneous velocity? I am not really sure and need some help
 
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The teacher covers the same distance both ways. You know that the distance he covered in all is twice that, and the time it took him each way can be obtained in terms of that distance. The average speed will just be the ratio of the total time to the total distance.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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