How to Solve for the Gamma-Ray Cross Section of Europium at 244.7 keV?

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SUMMARY

The discussion focuses on calculating the gamma-ray cross section for Europium at an energy peak of 244.7 keV. The mass attenuation coefficient was determined to be 8 x 10^-5 m²/kg, and the formula used for the cross section is σ = (μ * A) / N, where A is the molar mass, μ is the mass attenuation, and N is Avogadro's number. The calculated cross section appears small, prompting a discussion on the relevance of the energy peak in the equation.

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Homework Statement


Hi, I am trying to solve for the cross section for a gamma ray energy. The element I am using is Europium and the energy peak is 244.7 keV. From the slope of the graph I was able to determine the mass attenuation coefficient to be 8*10^-5 m^2/kg

Homework Equations


σ=(μ*A) / N

A- molar mass of the element
μ- mass attenuation
N- Avogadro's number
σ- cross section

The Attempt at a Solution


σ= ((8*10^-5)(63)) / (6.023*10^23)The solution to this seems very small.. I think that the equation that I am using should involve the energy peak... Any thoughts?? Thanks
 
Physics news on Phys.org
Check your units.

What do you mean by "very small"? Compare it to the typical size of a nucleus.
 

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