How to solve poisson process probabilities

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Homework Help Overview

The discussion revolves around a problem involving independent Poisson processes, specifically focusing on the conditional expectation E[X(1)|Z(2)=2]. Participants are exploring the relationships between the processes and the implications of their independence.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants are attempting to derive the conditional probability P(X(1)=k|Z(2)=2) and are breaking it down into components involving joint probabilities. There are questions regarding the understanding of the steps taken in the derivation, particularly concerning the independence of intervals and the application of Bayes' rule.

Discussion Status

Some participants have provided attempts at the solution but express confusion about the reasoning behind their steps. Questions have been raised about the rates of the Poisson processes, the validity of certain expressions, and the origins of specific factors in the equations. There is an ongoing exploration of the problem without a clear consensus on the correct approach.

Contextual Notes

Participants note that the rates of the Poisson processes are both 1, which is relevant to the calculations. There is also a mention of potential errors in the expressions presented, indicating a need for clarification and deeper understanding of the underlying concepts.

beyondlight
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Homework Statement



Let X(t) and Y(t) be independent Poisson processes, both with rates. Define Z(t)=X(t)+Y(t).
Find E[X(1)|Z(2)=2].



2. The attempt at a solution

[tex]P(X(1)=k|Z(2)=2)=P(X(1)=k|X(2)+Y(2)=2)=\frac{P(X(1)=k,X(2)+Y(2)=2)}{P(X(2)+Y(2)=2)}=\\\frac{P(X(1)=k,X(2)+Y(2)=2,Y(2)=0)+P(X(1)=k,X(2)+Y(2)=2,Y(2)=1)+P(X(1)=k,X(2)+Y(2)=2,Y(2)=2)}{P(X(2)=2,Y(2)=0)+P(X(2)=1,Y(2)=1)+P(X(2)=0,Y(2)=2)}[/tex]

Next step is following, let's call this part 2:

[tex]\frac{P(X(1)=k)P(X(2)-X(1)=2-k)P(Y(2)=0)+P(X(1)=K)P(X(2)-X(1)=1-k)P(Y(2)=1)+P(X(1)=k)P(X(2)-X(1)=-k)P(Y(2)=2)}{0.5e^{-2}+e^{-2}+0.5e^{-2}}[/tex]

This is further simplified (part 3):

[tex]0.5e[P(X(1)=k)P(X(1)=2-k)+P(X(1)=k)P(X(1)=1-k)+P(X(1)=k)P(X(1)=-k)0.5][/tex]

3. Basic theory

I know that two non-intersecting intervals are independent and that is why the expression X(2)-X(1) is desirable.

Bayes rule and the rule of independence are used in these equations.

However i do not understand the steps in the equations at all...Can someone explain how to think when solving this equation?
 
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beyondlight said:

Homework Statement



Let X(t) and Y(t) be independent Poisson processes, both with rates. Define Z(t)=X(t)+Y(t).
Find E[X(1)|Z(2)=2].



2. The attempt at a solution

[tex]P(X(1)=k|Z(2)=2)=P(X(1)=k|X(2)+Y(2)=2)=\frac{P(X(1)=k,X(2)+Y(2)=2)}{P(X(2)+Y(2)=2)}=\\\frac{P(X(1)=k,X(2)+Y(2)=2,Y(2)=0)+P(X(1)=k,X(2)+Y(2)=2,Y(2)=1)+P(X(1)=k,X(2)+Y(2)=2,Y(2)=2)}{P(X(2)=2,Y(2)=0)+P(X(2)=1,Y(2)=1)+P(X(2)=0,Y(2)=2)}[/tex]

Next step is following, let's call this part 2:

[tex]\frac{P(X(1)=k)P(X(2)-X(1)=2-k)P(Y(2)=0)+P(X(1)=K)P(X(2)-X(1)=1-k)P(Y(2)=1)+P(X(1)=k)P(X(2)-X(1)=-k)P(Y(2)=2)}{0.5e^{-2}+e^{-2}+0.5e^{-2}}[/tex]

This is further simplified (part 3):

[tex]0.5e[P(X(1)=k)P(X(1)=2-k)+P(X(1)=k)P(X(1)=1-k)+P(X(1)=k)P(X(1)=-k)0.5][/tex]

3. Basic theory

I know that two non-intersecting intervals are independent and that is why the expression X(2)-X(1) is desirable.

Bayes rule and the rule of independence are used in these equations.

However i do not understand the steps in the equations at all...Can someone explain how to think when solving this equation?

1) How can you be writing down equations that you do not understand? Are you copying them from somewhere?
2) What are the rates? You never told us that, and it certainly matters a lot.
3) Events like X(2)-X(1)=-k cannot occur if k ≥ 1---why not?
4) Where do the 0.5 factors come from? I think I can guess, but should not have to.
5) So, finally, what do the expressions simplify to? You need to figure that out in order to compute the conditional expectation.
 
1) i wrote them down from the answers.
2) rate is 1 for both variables
3)?
4)i plugg in the value k for either X or Z in the PMF for the Poisson random variable:
f=(1^ke^(-1))/k!

5) Right now I don't need help with the final answer, I just want to know how you should reason in order to get the expressions that i wrote down.
 
beyondlight said:
1) i wrote them down from the answers.
2) rate is 1 for both variables
3)?
4)i plugg in the value k for either X or Z in the PMF for the Poisson random variable:
f=(1^ke^(-1))/k!

5) Right now I don't need help with the final answer, I just want to know how you should reason in order to get the expressions that i wrote down.

You shouldn't, since the expressions you wrote down are wrong (at least, some of them are). Start over.
 

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