oszust001
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How can i solve that equation:
x^2 + y^2 = z^2-1 or x^2 + 3y^2 = z^2?
x^2 + y^2 = z^2-1 or x^2 + 3y^2 = z^2?
The discussion focuses on solving quadratic Diophantine equations in natural numbers, specifically the equations x² + y² = z² - 1 and x² + 3y² = z². Participants clarify that these equations require finding solutions where x, y, and z are all natural numbers. A key resource provided is a link to MathWorld, which outlines an explicit algorithm for solving such quadratic Diophantine equations, particularly in equations 6 to 10 of the referenced article.
PREREQUISITESMathematicians, students studying number theory, and anyone interested in solving quadratic Diophantine equations in natural numbers.
madah12 said:I don't think you can solve 3 variables with two equations but I am not sure.
Equations 6 to 10 of that article provide an explicit algorithm for solving exactly the kinds of problems specified in the original post.HallsofIvy said:Those are quadratic Diophantine equations. I don't know much about them myself by here is a link:http://mathworld.wolfram.com/DiophantineEquation2ndPowers.html