- #1

Jeno

- 17

- 0

## Homework Statement

(

**a**)^{2}+**a**·**b**- c = 0**a**and**b**are vectors which (in general) with different directions while c is a scalar. How to solve for**a**?## The Attempt at a Solution

(

(

(

**a**)^{2}+**a**·**b**- c = 0(

**a**+ (1/2)**b**)^{2}- (1/4)**b**^{2}- c = 0(

**a**+ (1/2)**b**)^{2}= (1/4)**b**^{2}+ cIn this case, if i carry the square from left hand side to right hand side, it appears that the left hand side turns into a vector while the right hand side remains as a scalar. I wonder why this happens and what would be the proper way to solve this equation.