How to Solve This Logarithmic Problem?

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You'll need these formulas

[tex]nlog_a b= log_a b^n[/tex]

[tex]log_a b= log_a c \Rightarrow b=c[/tex]

[tex]log_a x + log_a y = log_a xy[/tex]
 
phy_ said:
if i use these formulas

log(x-3)/3 = 1/2(logxy)

i am not sure what i would then do to have the answer resemble x squared + y squared = 11xy.

you mean you'd get log(x-y/3)= 1/2log(xy)?

Use first formula on 1/2log(xy) and then apply the second formula.
 
Thank-you very much. Question solved.