How to start Differential equation

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delsoo
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Mod note: Thread moved from technical math section. The OP has already been notified that this is not a suitable start to a request for homework help.[/color]
can anyone teach me how to start it? i really have no idea.. PART A
 
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  • Handwritten question 8: A particle has velocity v m/s and displacement x m from O, related by v^2 = 1 - e^(-2kx), where k is a constant. Show that (i) the maximum speed is 1 m/s, (ii) the acceleration is ke^(-2kx) m/s^2.
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You don't need to solve that equation for the two problems
The first problem amounts to finding a stationary point while the second requires you to implicitly differentiate that expression with respect to time.

Just a hint for i), the staionary point may only exist in a certain limit.
 
can you show the full working for part i please? i'd been thinking of this question for the whole day yet still can't get the ans
 
Here

Edit: In the last step I just plugged the value of x (which had to be done via a limit since it was positive infinty) back into the original expression for the answer
 
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  • Handwritten-style derivation: v^2 = 1 - e^(-2kx), then the derivative (v^2)' = 2ke^(-2kx) set to zero giving 0 = 2ke^(-2kx), then the limit as x tends to infinity of 1 - e^(-2kx) = 1.
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if i do this way then how should i proceed ? note: i want to find x first , then sub the value of x which i get into the eqaution 1... after arranging the terms, i would get ln 0 ... then i can't find the value of x ...
 
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  • Handwritten derivation: v^2 = 1 - e^(-2kx) labelled (1), then differentiating with respect to x gives 2v dv/dx = -2ke^(-2kx), which simplifies to v dv/dx = ke^(-2kx), and then 0 = ke^(-2kx).
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At the last step, you need to realize that the only way for the left hand side to equal zero is when x tends to positive infinity.