How to Transform a Piecewise Function Using the Second Shift Theorem?

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SUMMARY

The discussion focuses on transforming a piecewise function using the Second Shift Theorem in Laplace transforms. The piecewise function is defined as t(e^t) for 0 ≤ t ≤ 5 and 0 for t ≥ 3. The correct transformation involves expressing the function with the unit step function, leading to the formulation t(e^t) - (t-5)(e^(t-5))u(t-5). Participants emphasize the importance of careful step-by-step calculations to avoid errors in the transformation process.

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questions asks to write the piecewise function as a unit step function and then to find the laplace transform

t(e^t) 0≤t≤5
0 t≥3

I know it should be along the lines of

t(e^t) - t(e^t)u(t-5)

which then goes to

t(e^t) - (t-5)(e^(t-5))u(t-5)

I know there should be more to the above equation but I just can't figure out what to do from here
 
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robmass said:
questions asks to write the piecewise function as a unit step function and then to find the laplace transform

t(e^t) 0≤t≤5
0 t≥3

I know it should be along the lines of

t(e^t) - t(e^t)u(t-5)

which then goes to

t(e^t) - (t-5)(e^(t-5))u(t-5)

I know there should be more to the above equation but I just can't figure out what to do from here

Your second equation is wrong: you do not get simply (t-5)(e^(t-5))u(t-5). Work everything out carefully, step-by-step.
 

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