How to Use Nodal Analysis to Find Voltages in a Circuit?

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The discussion focuses on using the node-voltage method to calculate voltages v1 and v2 in a circuit with given currents. Initial attempts yielded incorrect values, prompting a reevaluation of the node assignments and resistor connections. It was suggested that nodes 2 and 3 could be combined, simplifying the equations. After adjusting the equations to include all relevant resistors, the correct values were found to be v1 = 114.7 V and v2 = 88 V. The importance of accurately incorporating all circuit elements in the analysis was emphasized.
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Homework Statement



Use the node-voltage method to find v1 in the circuit(Figure 1) if i1 = 6.2A and i2 = 1.5A .
Use the node-voltage method to find v2 in the circuit.

Figure_P04.8.jpg


Homework Equations



G = 1/R

QPFE3Hs.png


The Attempt at a Solution



Top side going from left to right, I assigned each node as 1, 3, then 2 (because of the way v_2 is assigned).

For Node 1, I had:
(v_1)/40 - (v_3)/8 = 6.2

Node 3:
-(v_1)/8 + (v_3)/80 = 0

Node 2:
(v_2)/120 = -1.5

Solving, I got v_1 = -5.06 V and v_2 = -180 V. These are wrong (obviously). Any assistance would be appreciated.

Moving image to bottom for visibility:

Figure_P04.8.jpg
 
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Hello G and welcome to PF. Clear story. Do you have a reason to assign node 3, or could you make do with just nodes 1 and 2 ?
Reason I ask is because V2 = V3 seems a reasonable assumption to me. (I will look up the thread where I made a complete fool of myself by completely missing such a thing -- fortunately others put me right...)

Found it -- don't laugh!
 
BvU said:
Hello G and welcome to PF. Clear story. Do you have a reason to assign node 3, or could you make do with just nodes 1 and 2 ?
Reason I ask is because V2 = V3 seems a reasonable assumption to me. (I will look up the thread where I made a complete fool of myself by completely missing such a thing -- fortunately others put me right...)

Found it -- don't laugh!

In that case where would I include the 80 Ohm resistor? Should it only be connected to v_2 on the equation?

If so,
Node 1:
6.2 = (v_1)/40 - (v_2)/8
-1.5 = (v_2)(1/80 + 1/120) - (v_1)/8

Solving, v_1 = 3.86 V and v_2 = -48.8 V. Which is still incorrect.

I'm out of attempts for solving for v_1, which I now know is 115 V.
 
Ah, I interpret the node a equation a little different: after all, the 8 ohm is also connected to node a !
 
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BvU said:
Ah, I interpret the node a equation a little different: after all, the 8 ohm is also connected to node a !

Ah, I see now. I didn't realize I had to include the resistors between each node as also connected to it individually.

1:
6.2 = v_1 * (1/40+1/8) - v_2 / 8

2:
-1.5 = v_2 * (1/80 + 1/120 + 1/8) - v_1 / 8

Ended with v_1 = 114.7 and v_2 = 88 (which is correct). Thanks.
 
Always nice to have the answer at hand... I was still plodding :smile:
And: you're welcome!
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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