How to work out this impact force

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Homework Help Overview

The discussion revolves around calculating the impact force experienced by a driver during a Formula 1 crash, where a car traveling at 172.8 km/h comes to a stop in 0.0272 seconds. The problem involves concepts from dynamics and kinematics, specifically relating to force, mass, and acceleration.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants explore the relationship between force, mass, and acceleration, questioning the correct application of formulas. There is a focus on determining the acceleration (or deceleration) of the car upon impact and converting units from km/h to m/s.

Discussion Status

Participants are actively engaging with the problem, discussing unit conversions and the appropriate formulas to use. Some have provided guidance on the calculations, while others are verifying the correctness of units and values. There is no explicit consensus on the final solution yet, but the conversation is progressing towards clarity.

Contextual Notes

There are indications of confusion regarding the units of acceleration and the application of the formulas involved. Participants are also reflecting on the implications of the scenario presented, considering the extreme nature of the forces involved in such a crash.

Lily May
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Homework Statement


During a Formula 1 race a car that was traveling at a speed of 172.8 km/h crashed into a wall. When the car hit the wall it came to a complete stop in 0.0272 s. If the driver of the car holds a mass of 70kg, calculate the impact force he experienced.

Homework Equations


I honestly don't know. F = m*a or F= GMm/r^2

The Attempt at a Solution


I have no idea what to do?
F= m*a
= 70*172.8
= 12 096N
 
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Lily May said:

Homework Equations


I honestly don't know. F = m*a or F= GMm/r^2
I don't think gravity will have anything to do with this problem, so you can forget that last equation.

Lily May said:

The Attempt at a Solution


I have no idea what to do?
F= m*a
= 70*172.8
= 12 096N
What is the acceleration (meaning "deceleration" in this case) of the car as it hits the wall?
 
Lily May said:
F= m*a
= 70*172.8

Does the unit for acceleration match the unit of the number you've plugged in for 'a'? If not, how might you get that unit from the information provided?
 
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DrClaude said:
I don't think gravity will have anything to do with this problem, so you can forget that last equation.What is the acceleration (meaning "deceleration" in this case) of the car as it hits the wall?
Am I meant to use the acceleration formula for that?
a= v1 - v2 / t
 
Lily May said:
Am I meant to use the acceleration formula for that?
a= v1 - v2 / t
Yes. [But it should be v2 - v1 if v2 is the final velocity. And parentheses can be helpful: a = (v2 - v1)/t.]
 
Drakkith said:
Does the unit for acceleration match the unit of the number you've plugged in for 'a'? If not, how might you get that unit from the information provided?

So you'd have to mutiple the number by 1000 then divide by 3600?
172.8*1000= 172800
172800/3600= 48m/s/s
 
Lily May said:
So you'd have to mutiple the number by 1000 then divide by 3600?
172.8*1000= 172800
172800/3600= 48m/s/s
Put units everywhere:
$$
\begin{align*}
172.8\frac{\mathrm{km}}{\mathrm{h}} \times \frac{1000\ \mathrm{m}}{\mathrm{km}} &= 172800 \frac{\mathrm{m}}{\mathrm{h}} \\
172800 \frac{\mathrm{m}}{\mathrm{h}} \times \frac{\mathrm{h}}{3600\ \mathrm{s}} &= 48 \frac{\mathrm{m}}{\mathrm{s}}
\end{align*}
$$
 
DrClaude said:
Yes. [But it should be v2 - v1 if v2 is the final velocity. And parentheses can be helpful: a = (v2 - v1)/t.]

So
v2 = 0?
v1= 48m/s^2
t = 0.0272s
 
Lily May said:
So you'd have to mutiple the number by 1000 then divide by 3600?
172.8*1000= 172800
172800/3600= 48m/s/s

DC seems to be helping you well at the moment. I'm going to step out and let him handle it for now. I'll pop back in later though.
 
  • #10
DrClaude said:
Put units everywhere:
$$
\begin{align*}
172.8\frac{\mathrm{km}}{\mathrm{h}} \times \frac{1000\ \mathrm{m}}{\mathrm{km}} &= 172800 \frac{\mathrm{m}}{\mathrm{h}} \\
172800 \frac{\mathrm{m}}{\mathrm{h}} \times \frac{\mathrm{h}}{3600\ \mathrm{s}} &= 48 \frac{\mathrm{m}}{\mathrm{s}}
\end{align*}
$$
Whoops, I'll be sure to do that, thanks. So then do I use the acceleration fomula or the force fomula?
 
  • #11
Lily May said:
So
v2 = 0?
v1= 48m/s^2
t = 0.0272s
Are you sure about the units of v1? What is the acceleration?
 
  • #12
DrClaude said:
Are you sure about the units of v1? What is the acceleration?
v1 = 48m/s
a = (v2 - v1)/t.]
= 0 - 48m/s
= -48m/s / 0.0272s
a = -1 764.71m/s
that doesn't seem right
 
  • #13
Lily May said:
v1 = 48m/s
a = (v2 - v1)/t.]
= 0 - 48m/s
= -48m/s / 0.0272s
a = -1 764.71m/s
that doesn't seem right
Units... if you divide meters per second by seconds, what do you get?
 
  • #14
Lily May said:
v1 = 48m/s
a = (v2 - v1)/t.]
= 0 - 48m/s
= -48m/s / 0.0272s
a = -1 764.71m/s
that doesn't seem right

The math looks correct, you just have it in units of velocity instead of acceleration.
 
  • #15
Drakkith said:
The math looks correct, you just have it in units of velocity instead of acceleration.
So I'd just change the end to -1 764.71m/s^2 = a
And mass = 70kg
Then I multiple those two together to get the impact force/final answer?
 
  • #16
Lily May said:
So I'd just change the end to -1 764.71m/s^2 = a
And mass = 70kg
Then I multiple those two together to get the impact force/final answer?
Correct.
 
  • #17
DrClaude said:
Correct.
Thank you all!
 
  • #18
Bit of a macabre exercise. 180 g can not be survived by a human. This looks like a post mortem review ..
Fortunately head-on crashes with concrete walls are rare in F1.
 
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