How was the matrix in the attachment found

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  • Thread starter LSMOG
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  • #1
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15273519438341685572088.jpg
I understand the dot product of ei.ej, but I can't find the matrix components.
 

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  • #2
martinbn
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I understand the dot product of ei.ej, but I can't find the matrix components.
The matrix components are these dot products.
 
  • #3
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Thanks. I've managed to find the matrix above by finding the dot products. Now how was ds2 = dr2+r22+r2 sin2θ dΦ2 found?
 
  • #5
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You can get it by inserting
[tex]x=r\ sin\theta\ cos\phi[/tex]
[tex]y=r\ sin\theta\ sin\phi[/tex]
[tex]z=r\ cos\ \theta[/tex]
into
[tex]dx^2+dy^2+dz^2[/tex]
 
  • #6
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You can get it by inserting
[tex]x=r\ sin\theta\ cos\phi[/tex]
[tex]y=r\ sin\theta\ sin\phi[/tex]
[tex]z=r\ cos\ \theta[/tex]
into
[tex]dx^2+dy^2+dz^2[/tex]
Thank you. But you you gave x, y and z in spherical coordinates, according to your last expression, I need dx, dy and dx in spherical coordinates.
 
  • #7
Dr Transport
Science Advisor
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Thank you. But you you gave x, y and z in spherical coordinates, according to your last expression, I need dx, dy and dx in spherical coordinates.
do the derivatives
 

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