How/when can I take a wave function and its complex conjugate as independent?

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
1 reply · 2K views
SiggyYo
Messages
5
Reaction score
0
For the last step in the derivation of the Gross-Pitaevskii equation, we have the following equation
[itex]0=\int \eta^*(gNh\phi+gN^2\phi^*\phi^2-N\mu\phi)\ dV+\int (N\phi^*h+gN^2(\phi^2)^*\phi-N\mu\phi^*)\eta\ dV,[/itex]
where [itex]\eta[/itex] is an arbitrary function, [itex]g,N,\mu[/itex] are constants, [itex]h[/itex] is the hamiltonian for the harmonic oscillator and [itex]\phi[/itex] is the ground state of the hamiltonian.

Now, the last step involves seeing that this can only be the case if [itex]gNh\phi+gN^2\phi^*\phi^2-N\mu\phi[/itex] and [itex]N\phi^*h+gN^2(\phi^2)^*\phi-N\mu\phi^*[/itex] are both zero. As far as I can tell, I would need an argument that [itex]\phi[/itex] and [itex]\phi^*[/itex] are independent for this to be true.

Can anyone explain why this is the case (or in case I'm wrong, explain what else I need to consider)?

Thanks,
 
Physics news on Phys.org
Write it as ∫ η* A dV + ∫ η B dV = 0, and let η = α + i β where α, β are arbitrary real functions. Then ∫ [α (A + B) + β (-iA + iB)] dV = 0. This can only happen if A + B and A - B are both zero, in other words A and B are both zero. You don't have to assume anything about φ.