Undergrad How Would Afshar's Experiment Affect Entanglement?

Click For Summary
Afshar's experiment, which involves sending a light beam through a double-slit setup, raises questions about the effects on entanglement when using entangled photons. It is expected that momentum entanglement would be broken due to diffraction at the slits. However, there is speculation that path entanglement could be preserved if the beam is split using a non-polarizing beam splitter, allowing overlapping and interference. Polarization entanglement is likely to remain intact since the experiment does not measure or collapse the polarization state. Overall, the discussion highlights the complexities of entanglement preservation in various experimental setups.
Erik Ayer
Messages
78
Reaction score
4
TL;DR
If one of the two beams from non-colinear SPDC were sent through Afshar's experiment, would momentum, path, and/or polarization entanglement be broken?
Afshar's experiment (https://en.wikipedia.org/wiki/Afshar_experiment) sent a light beam through a double-slit to get interference, put wires in the places where there were dark fringes, then refocused the light with a lens get "image" the two slits. I'm wondering what entanglements would break if one beam from an entangled source were sent through Afshar's experiment. To keep this slightly simple, assume the two beams with entangled photons are from type 2 SPDC and are not colinear - they two beams go in different directions.

What I would expect is that momentum entanglement would be broken when the beam went through the slits and diffracted. However, I wonder whether it could be preserved if, instead of slit, the beam were split with a regular old (non-polarizing) beam splitter and the two sub-beams made to overlap and interfere with a lens. My guess would be that path entanglement would survive since a photon going through the left slit would end up in the left image and one going through the right slit would end up in the right image after the lens. Polarization entanglement would survive since Afshar's experiment does nothing to measure or collapse the polarization state of superposition.
 
Physics news on Phys.org
The dark spots that you'd put the wires in will not be present when the photon is entangled with another photon. You won't be able to find a spot where a detector never clicks. Ignoring that and putting the wires in the usual place would be equivalent to measuring the photon in the "left slit + right slit vs left slit - right slit" basis (or something of that nature), downgrading the entanglement between the two photons into correlation.
 
Thank you for your response! If I understand correctly, the momentum entanglement would be destroyed. I'm not sure about path entanglement of whether it even makes sense to ask about that. However, would polarization entanglement remain intact? It seems like it should.
 
Time reversal invariant Hamiltonians must satisfy ##[H,\Theta]=0## where ##\Theta## is time reversal operator. However, in some texts (for example see Many-body Quantum Theory in Condensed Matter Physics an introduction, HENRIK BRUUS and KARSTEN FLENSBERG, Corrected version: 14 January 2016, section 7.1.4) the time reversal invariant condition is introduced as ##H=H^*##. How these two conditions are identical?

Similar threads

  • · Replies 7 ·
Replies
7
Views
914
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 20 ·
Replies
20
Views
2K
  • · Replies 16 ·
Replies
16
Views
3K
  • · Replies 41 ·
2
Replies
41
Views
6K
  • · Replies 24 ·
Replies
24
Views
3K
  • · Replies 2 ·
Replies
2
Views
1K
Replies
2
Views
2K