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Hubble's law and cosmological density

  1. Mar 24, 2012 #1
    While reading I came across this chart in Wikipedia

    http://en.wikipedia.org/wiki/Metric_expansion_of_space

    Anybody know the source or a similar plot with some explanations? What do you make of it?? What does it purport to show? Is it in the correct section [Theoretical basis and first evidence] of the article.....If so which is it: do you think the plot represents a 'theoretial basis', a prediction, or does it suggest 'first evidence' , experimental confirmation..?

    The y axis is p(a) and the x axis a(t)......is (a) cosmological scale factor??....so where "today" on the chart is about 3ct0...or 42B years or so?

    I can see that radiation density falls off most rapidly (proportional to 1/a4, matter density falls off with volume, curvature as 1/a2, and dark energy density remains constant....is it obvious the first three decline linearly?

    So far I haven't found a title, explanation, legend, or anything else....Apparently it was posted March 12, 2012.... so it seems pretty new. Maybe Muhammad the author will add more..

    Why are matter and radiation shown at a common starting point with equal densities...?
    Why that point was selected??? I'm guessing it's because nobody knows the radiation density at the big bang, so its convenient..or is that where linear change can be approximated for those two variables??

    thanks.....
     
  2. jcsd
  3. Mar 24, 2012 #2

    Nabeshin

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    I think what you're missing is that this is meant to be a log plot. In the radiation dominated universe, [itex]a \propto \sqrt{t}[/itex], so [itex] \log a \propto 1/2 \log t[/itex], which is of course a straight line with slope 1/2 in log-log space. Similarly for matter dominated, the curvature term, and of course DE dominated is constant. The plot is usually used to show the various epochs in our universe's history, such as the matter-radiation equality, along with the transition into a de-Sitter universe.

    That should clear it up, I think.
     
  4. Mar 24, 2012 #3

    marcus

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    Dearly Missed

  5. Mar 25, 2012 #4

    Chalnoth

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    As others have mentioned, this is a logarithmic plot. Variables with power-law relationships look linear on a log-log plot.

    They don't start off at equal densities. But because radiation is decreasing in density faster, at some point they do have equal densities.

    And by the way, the radiation density at the emission of the CMB is extremely well-known, and we can extrapolate the previous radiation density back in time from there. At some point that extrapolation obviously has to break down.
     
  6. Mar 25, 2012 #5
    Apparently I am 'out of touch' with with 'new' graphing techniques of no title, no axis labels, no legend, ...well, not even any text.... You guys and girls will have to excuse me for being unable to start from scratch....next time I plot something, I think I'll just plot the variables: why bother with axis, labels, etc...makes stuff more 'mysterious'.....and maybe I'll rotate 1/4 turn from standard plots for additional 'coolness'....I DON"T THINK SO!!!

    I AM missing a lot more than that!!!! but that insight DOES help!!! [Can I get 'half credit' for recognizing that all those linear declines would be really, really unusual??]

    nicely stated....
    but I still don't know why equal matter and radiation densities were picked....although it does look rather nice that way!....that didn't coincidentally happen at the first CMB emission, right?? It appears a specific scale factor was picked, aeq which if 'eq' means equal I'll take a stab in the dark an guess it means when matter and radiation density were equal......??

    this #$*&^% confounded graph got me all distracted from the scale factor and metric expansion I was trying to read more about.....now somebody admit it: doesn't a graph need something besides greek letters!!!
     
  7. Mar 25, 2012 #6

    Chalnoth

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    No need to get snarky. Obviously it's a badly-composed plot. We only know what it means because we're familiar with this sort of thing.

    It's just a plotting choice. Nothing special about it. They simply chose to start the plot just before matter and radiation reached equality. There was a fair amount of time before that.

    No, no. Matter/radiation equality was quite a bit earlier.

    Yes, that's the usual label for the particular time when matter and radiation had equal densities.
     
  8. Mar 25, 2012 #7

    Chalnoth

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    Oh, interesting. Just looked at the plot again. This plot also doesn't conform to reality. That's probably part of why it's so vague: it's simply a plot of what the various energy densities do over time. But the particular energy densities just don't match reality at all.

    How do I know this? Well, it lists a substantial "energy density" for curvature at the present time. This just isn't the case.

    So it's just a heuristic plot to show how the different sorts of energy densities change over time.

    Note: I put energy density in quotes for curvature because it isn't really an energy density. But it acts much like one when considering its effect on the expansion.
     
  9. Mar 25, 2012 #8
    Chalnoth..ha,ha...same thing happened to you as to me... that darn graph has me distracted!!!

    You may be right, but I'm not so sure ....take a look at the defined intersection points to the right where some x axis points are labelled [like ρcλ....where the curvature line seems anchored]......I don't know what those mean but somebody seems to have had something specific in mind.....????
     
  10. Mar 25, 2012 #9

    Chalnoth

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    Look at the point that says "present day." It shows [itex]\rho_c > \rho_\Lambda[/itex], which is definitely not the case.
     
  11. Mar 25, 2012 #10
    My whole issue is that I don't know what those symbols mean...I can infer from the chart what ρλ means...cause dark matter density supposedly remains constant but that's about it....
     
  12. Mar 25, 2012 #11

    Chalnoth

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    Okay, so, [itex]a[/itex] is the scale factor, and each [itex]\rho[/itex] is a different energy density. Specifically, [itex]\rho_r[/itex] is the radiation energy density, [itex]\rho_m[/itex] is the matter energy density, [itex]\rho_\Lambda[/itex] is the dark energy density, and [itex]\rho_c[/itex] is the effective curvature density.

    Does that help?
     
  13. Mar 26, 2012 #12
    DUH!!!

    I kept thinking "c" for lightspeed ......but I am laboring from the disadvantage of never having heard of 'curvature density'....What is that??

    Anything to do with any of this:

    http://en.wikipedia.org/wiki/Scalar_curvature
     
  14. Mar 26, 2012 #13
    really ?
    hmmmm
     
  15. Mar 26, 2012 #14

    Nabeshin

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  16. Mar 26, 2012 #15

    Nabeshin

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    Yeah, that's basically the hallmark of Dark Energy, and why it connects back to Einstein's cosmological constant rather than a standard matter density.
     
    Last edited: Mar 26, 2012
  17. Mar 26, 2012 #16

    Chalnoth

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    Not really. At least, not exactly. The scalar curvature in the FRW metric has two components: one stemming from the expansion itself, the other coming from the spatial curvature. This term, [itex]\rho_c[/itex] is only related to the spatial curvature.

    Taking the first Friedmann equation, for example:

    [tex]H^2 = {8\pi G \over 3}\rho - {kc^2 \over a^2}[/tex]

    The parameter [itex]\rho_c[/itex] is simply defined so that it contains the information of the curvature parameter [itex]k[/itex], but enters this equation like an energy density:

    [tex]\rho_c = {-3kc^2 \over 8\pi Ga^2}[/tex]

    So that now we can write the first Friedmann equation as:

    [tex]H^2 = {8 \pi G \over 3} \tilde{\rho}[/tex]

    With:

    [tex]\tilde{\rho} = \rho + \rho_c[/tex]
     
  18. Mar 26, 2012 #17

    cepheid

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    Naty1 actually said that the dark *matter* density was constant, which may have been why lostprophets questioned him.

    Also, if w != -1 then the dark energy density is not constant and can't be described simply as a cosmological constant term.
     
  19. Mar 27, 2012 #18

    Nabeshin

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    Oops! Of course, you can have w != -1, but in the standard Lambda-CDM it's taken to be -1.
     
  20. Mar 27, 2012 #19
    ρ
    oops for me too..I meant to say 'energy' density...



    Nabeshin: thank's for the reference

    tp://en.wikipedia.org/wiki/Friedma...#The_equations



    so the ρc is CRITICAL density.... Now I understand Chalnoth's comment:

    I've only seen critical density referred to as an 'energy density' rather than a 'spatial curvature' as well.....

    I sure have to keep a CLOSE watch on you guys!!! Thanks.
     
    Last edited: Mar 27, 2012
  21. Mar 27, 2012 #20
    Can someone explain what 'w' is in posts #17 and #18. Is this an easy way to write
    Ω, that is actual/critical density...??

    All I think I know is that 'new' space causes cosmological expansion, 'arrives' with it's own energy density, same as old space, and so with more space we get more cosmological total energy....we call it negative vacuum energy pressure.....

    [Now that I have noticed 'quick symbols' to the right of my when posting [is that new?] screen I could get even more 'dangerous' posting stuff like Ω.....cool!!]
     
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