1. The problem statement, all variables and given/known data A 45 kg woman jumps from a height of 2.5 meters to a solid floor. In an attempt to minimize the likelihood of injury, she lands on the ball of her feet (the pads just behind her toes) with her knees bent. What average force is needed on her feet to stop her fall if her center-of-gravity after touching the floor drops 80 cm before she stops? If the horizontal distance from the ball of her foot to her talus (where her tibia exerts its force) is 15 cm, and from talus back to the Achilles tendon is 3.6 cm, what average force does the Achilles tendon suffer during the stopping time 2. Relevant equations F = ma vf^2 = vi^2 + 2ad 3. The attempt at a solution I've solved for vf = 7 m/s and the average deceleration of the woman (49/(2*.8m)) = 30.625 and even got to an average force answer of 6028.13 newtons per second using average deceleration and time but just got stuck from there. Can anybody help me out?