Hydrogen Atom Wavefunction Boundary conditions

Click For Summary
The discussion centers on solving the differential equation for the Hydrogen atom's wavefunction in the ground state using Euler's method. The equation provided includes terms for the potential V(r) and requires initial conditions for the wavefunction and its first derivative. The challenge arises at r = 0, where certain terms become infinite, complicating the determination of a second derivative initial condition. It is suggested that instead of seeking a third initial condition, one should adjust the energy value, known as the shooting parameter, to find the correct wavefunction. This approach will ensure the wavefunction decays to zero at infinity.
Chris333
Messages
1
Reaction score
0
Hi, I have been given a differential equation to use in order to solve for the Hydrogen wavefunction in the ground state using Euler's method.

d^2u_nl/dr^2 -(l(l+1)/r^2)*u_nl + 2k*(E_nl-V(r))*u_nl = 0

V(r) = -a/r where a = 1/137.04

I have been given initial conditions u_nl(0) = 0 an du_nl(0)/dr = 1
However I need an initial value for the second derivative in order to proceed.

At r = 0, l(l+1/r^2 goes to infinity as does V(r) so I'm not sure what initial condition to use. Any help would be much appreciated.
 
Physics news on Phys.org
You already have two initial conditions for u_{nl} and there is no need for a third one.
You will find the right wavefunction by adjusting the value of the energy, which in this case is called the shooting parameter. Varying the value of the energy you will find the wavefunction decay at zero at infinity.
 
Time reversal invariant Hamiltonians must satisfy ##[H,\Theta]=0## where ##\Theta## is time reversal operator. However, in some texts (for example see Many-body Quantum Theory in Condensed Matter Physics an introduction, HENRIK BRUUS and KARSTEN FLENSBERG, Corrected version: 14 January 2016, section 7.1.4) the time reversal invariant condition is introduced as ##H=H^*##. How these two conditions are identical?

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 22 ·
Replies
22
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 17 ·
Replies
17
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 5 ·
Replies
5
Views
1K