Hydrostatics: solving for density.

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SUMMARY

The discussion focuses on solving a hydrostatics problem involving a block of wood floating in water and oil. The density of the wood is calculated as 2/3 the density of water, while the density of the oil is determined to be 20/27 the density of water. The final conclusion establishes the order of densities as wood < oil < water, confirming the accuracy of the calculations presented.

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Homework Statement


A block of wood floats in water with 2/3 of its volume submerged. In oil, it does so with 9/10 of it submerged. Find the density of the block of wood and the oil in terms of water's density.


The Attempt at a Solution



Setting the equilibrium condition (net force = 0) I get:

\rho(wood) = 2/3 \rho(water)

then \rho(oil) = 10/9 \rho(wood) which is = 20/27 \rho(water)

So in increasing order of density, I've got: wood < oil < water.

Just wanted to check if this was correct, thanks.
 
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