Undergrad Hyperfine Splitting: Get Help Understanding It

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    Hyperfine Splitting
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Hyperfine splitting is described by the formula ΔE_hfs = -μ_I · B_J = (a/2)[F(F+1) - I(I+1) - J(J+1)], where 'a' is determined by the nuclear magnetic moment and the magnetic field. For Titanium-48, which has no nuclear spin (I=0), hyperfine splitting does not occur, resulting in no observable effects. Understanding the values of I, J, and F is crucial for calculating hyperfine splitting in other isotopes. The discussion emphasizes the importance of these quantum numbers in determining the presence of hyperfine splitting. Therefore, for isotopes like Titanium-48, hyperfine splitting is absent due to the lack of nuclear spin.
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I'm trying to figure out how to find the energy difference of Titanium-48(22 protons/electrons & 26 neutrons) hyperfine splits of the ground state. It has 2 unpaired electrons(d orbital) and angular momentum of 2(l=2) so the total splits(2l+1) are 5.
I've looked around for help on sites and youtube but I don't really understand how to figure it out.
 
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The formula of hyperstructure splitting
{\displaystyle \Delta E_{hfs}=-{\vec {\mu }}_{I}{\vec {B}}_{J}={\frac {a}{2}}[F(F+1)-I(I+1)-J(J+1)],}
where
{\displaystyle a={\frac {g_{I}{\vec {\mu }}_{N}{\vec {B}}_{J}}{\sqrt {J(J+1)}}},} , J is the rotational quantum number and F is the total rotational quantum number inclusive of nuclear spin I via
https://en.wikipedia.org/wiki/Hyperfine_structure.

How about finding these I,J and F in your case ?
 
Titanium-48 has no nuclear spin, ##I=0##, so there will be no hyperfine splitting.
 
Time reversal invariant Hamiltonians must satisfy ##[H,\Theta]=0## where ##\Theta## is time reversal operator. However, in some texts (for example see Many-body Quantum Theory in Condensed Matter Physics an introduction, HENRIK BRUUS and KARSTEN FLENSBERG, Corrected version: 14 January 2016, section 7.1.4) the time reversal invariant condition is introduced as ##H=H^*##. How these two conditions are identical?

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