Hyperfine splitting of deuterium

Click For Summary

Homework Help Overview

The discussion revolves around calculating the wavelength of a photon emitted during a hyperfine transition in the ground state of deuterium, which consists of a proton and a neutron in the nucleus. The problem involves understanding the spin states and magnetic moments associated with deuterium.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the calculation of expectation values related to spin states and the total spin vector. There is mention of using Clebsch-Gordan tables to assist in the calculations. Questions arise regarding how to properly add the spins for the total spin vector and the implications of different spin states.

Discussion Status

Some participants have provided guidance on using specific mathematical tools, such as Clebsch-Gordan tables, to aid in the calculations. There is an ongoing exploration of the spin values and their contributions to the total angular momentum, but no consensus has been reached on the final approach or solution.

Contextual Notes

The original poster expresses difficulty in adding the spins for the total spin vector and understanding the implications of the spin states. There is a focus on the quantum mechanical aspects of the problem, particularly concerning the spins of the electron and deuterium.

Aaronse_r
Messages
10
Reaction score
0
[SOLVED] Hyperfine splitting of deuterium

Homework Statement


Calculate the wavelength of the photon emitted under a hyperfine transition in the ground state (n=1) of deuterium. Deuterium is a proton and a neutron in the nucleus, but still one electron. The spin of deuterium is 1.

Homework Equations



H prime=(magnetic moment)* B-field

mag moment of electron = (g-factor*e) / m_e
mag moment of deuterium = (g-factor*e) / (2m_d) g-factor for deut = 1.71

The Attempt at a Solution



I was able to solve up to the part where you get the expectation values...something like <S^2 - S(d)^2 - S(e)^2>. [the S(e) and S(d) are spin of electron and deuterium, sorry it's hard to read]

I don't know how to add the spins for the total spin vector though. My attempt at the spin states was this.

m = 1+1/2
m = 1/2
m = -1/2
m = -3/2

So S can be any of these values time hbar, and S^2 is hbar^2 *m(m+1)
 
Last edited:
Physics news on Phys.org
Use clebsh gordan tables.
 
Thank you i will try to make some sense of that thing!
 
S= 3/2 and 1/2
 
Last edited:
You need s.S for s= spin 1/2 and S= spin 3/2.
Since J=s+S, you get 2s.S=J^2-S^2-s^2=j(j+1)-2-3/2.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 3 ·
Replies
3
Views
3K
Replies
17
Views
3K
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 0 ·
Replies
0
Views
2K
  • · Replies 5 ·
Replies
5
Views
792
Replies
8
Views
3K