Hyperfine splitting of deuterium

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SUMMARY

The discussion focuses on calculating the wavelength of the photon emitted during a hyperfine transition in the ground state (n=1) of deuterium, which consists of one proton and one neutron. The magnetic moment of deuterium is derived using the g-factor of 1.71, and the magnetic moment formula is applied: (g-factor * e) / (2 * m_d). The user successfully computes expectation values but struggles with combining the spins of the electron and deuterium to find the total spin vector.

PREREQUISITES
  • Understanding of hyperfine splitting in atomic physics
  • Familiarity with magnetic moments and g-factors
  • Knowledge of quantum mechanics, specifically spin and angular momentum
  • Experience with Clebsch-Gordan coefficients for adding angular momenta
NEXT STEPS
  • Study the calculation of hyperfine splitting in hydrogen-like atoms
  • Learn about the application of Clebsch-Gordan coefficients in quantum mechanics
  • Explore the derivation of magnetic moments for different particles
  • Investigate the implications of spin states in quantum systems
USEFUL FOR

Students and researchers in atomic physics, particularly those focused on hyperfine interactions and quantum mechanics, will benefit from this discussion.

Aaronse_r
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[SOLVED] Hyperfine splitting of deuterium

Homework Statement


Calculate the wavelength of the photon emitted under a hyperfine transition in the ground state (n=1) of deuterium. Deuterium is a proton and a neutron in the nucleus, but still one electron. The spin of deuterium is 1.

Homework Equations



H prime=(magnetic moment)* B-field

mag moment of electron = (g-factor*e) / m_e
mag moment of deuterium = (g-factor*e) / (2m_d) g-factor for deut = 1.71

The Attempt at a Solution



I was able to solve up to the part where you get the expectation values...something like <S^2 - S(d)^2 - S(e)^2>. [the S(e) and S(d) are spin of electron and deuterium, sorry it's hard to read]

I don't know how to add the spins for the total spin vector though. My attempt at the spin states was this.

m = 1+1/2
m = 1/2
m = -1/2
m = -3/2

So S can be any of these values time hbar, and S^2 is hbar^2 *m(m+1)
 
Last edited:
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Use clebsh gordan tables.
 
Thank you i will try to make some sense of that thing!
 
S= 3/2 and 1/2
 
Last edited:
You need s.S for s= spin 1/2 and S= spin 3/2.
Since J=s+S, you get 2s.S=J^2-S^2-s^2=j(j+1)-2-3/2.
 

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