Hypertonic / Hypotonic - A solution containing 0.2 M KCl

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SUMMARY

A solution containing 0.2 M KCl is added to Side A, while a solution containing 0.2 M sucrose is added to Side B. Due to the dissociation of KCl into K+ and Cl-, Side A effectively has a concentration of 0.4 M of solute particles, making it hypertonic compared to Side B, which remains at 0.2 M. Therefore, Side B is hypotonic with respect to Side A. This conclusion is based on the principles of osmotic concentration and solute dissociation.

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Homework Statement


A solution containing 0.2 M KCl is added to Side A and a solution containing 0.2 M sucrose is added to Side B.
Side B is __________ with respect to Side A. (a. hypotonic b. isotonic c. hypertonic.

Homework Equations


NA

The Attempt at a Solution


I have no idea. I know that the hypertonic side would be the side with the greater concentration, or the opposite for hypotonic.
Here we have different solutions, but the same concentration.

Thanks for any help you can give me!
 
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KCl dissociates, so you'll have 0.2M or K+ and 0.2M of Cl-... Therefore solution A is twice as concentrated as solution B (sucrose cannot dissociate)... Therefore, "Side B is hypotonic with respect to Side A"
 
Thank you so much!
 

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