I dont understand how to find acceleration for the second part

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for the first two I used the equation a=v^2/r
but for the second part I don't know what it is asking for or how to approach it. is there an equation that goes with it?
 

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the 1st two are wrong when I use a=v/r it is also wrong, and I converted km/h to m/s
 
Hi Sneakatone! :smile:

a = v2/r should be correct.

How exactly did you get 74.3 and 197.7 ? :confused:
 
[tex]a= v^2/r[/tex] will give the acceleration due to the motion around the circle. The actual force the pilot experiences will be those plus or minus the weight of the pilot.
 
the diameter is 300 so 1/2 of it is 150 , that's where I got it. and then I tried using the whole diameter ans that is not right
 
well sonb , I can't believe I didnt see that thanks!
now that we have that I still don't know how to do the second part.
 
Sneakatone said:
… I still don't know how to do the second part.

you mean the centripetal acceleration at the bottom?

same method :smile:
 
do you mean the third part? :confused:

yes, you have to take gravity into account
 
Im thinking it would be something like 22.1-(1/2*9.82) because gravity is downward on a horizontal acceleration.?
 
you're doing it again!

where do those figures come from? :cry:
 
the way I am thinkg of it is that the found acceleration which is 22.1 is being acted upon a down ward acceleration of gravity.

how would you do this?
 
I believe not , i don't even know which equation I should appy
 
I believe not , I ont even know which equaton to apply.
it seems like w^2r is a possibility.