I dont understand how to find acceleration for the second part

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Homework Help Overview

The discussion revolves around understanding how to find acceleration in a physics problem related to circular motion. Participants are trying to clarify the equations and concepts involved, particularly in the context of centripetal acceleration and the effects of gravity.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the use of the equation a = v^2/r for calculating acceleration and question its application in different parts of the problem. There are attempts to clarify the correct radius to use and how gravity affects the acceleration in a circular motion context.

Discussion Status

The discussion is ongoing, with participants providing insights and questioning each other's reasoning. Some guidance has been offered regarding the equations to consider, but there is still uncertainty about how to approach the second part of the problem and the role of gravity.

Contextual Notes

There is confusion regarding the correct diameter and radius to use in calculations, as well as uncertainty about the equations applicable to the problem. Participants are also exploring the implications of gravity on the acceleration being calculated.

Sneakatone
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for the first two I used the equation a=v^2/r
but for the second part I don't know what it is asking for or how to approach it. is there an equation that goes with it?
 

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the 1st two are wrong when I use a=v/r it is also wrong, and I converted km/h to m/s
 
Hi Sneakatone! :smile:

a = v2/r should be correct.

How exactly did you get 74.3 and 197.7 ? :confused:
 
[tex]a= v^2/r[/tex] will give the acceleration due to the motion around the circle. The actual force the pilot experiences will be those plus or minus the weight of the pilot.
 
105.5^2/150=74.2 m/s
172.22^2/150= 197.7 ms
 
erm :redface:

it's not 150 ! :wink:
 
the diameter is 300 so 1/2 of it is 150 , that's where I got it. and then I tried using the whole diameter ans that is not right
 
no, the diameter is 1000 :wink:
 
well sonb , I can't believe I didnt see that thanks!
now that we have that I still don't know how to do the second part.
 
  • #10
Sneakatone said:
… I still don't know how to do the second part.

you mean the centripetal acceleration at the bottom?

same method :smile:
 
  • #11
would i use gravity and the magnitude?
 
  • #12
do you mean the third part? :confused:

yes, you have to take gravity into account
 
  • #13
Im thinking it would be something like 22.1-(1/2*9.82) because gravity is downward on a horizontal acceleration.?
 
  • #14
you're doing it again!

where do those figures come from? :cry:
 
  • #15
the way I am thinkg of it is that the found acceleration which is 22.1 is being acted upon a down ward acceleration of gravity.

how would you do this?
 
  • #16
(i don't make it exactly 22.1)

where did the 1/2 come from? :confused:

has your professor taught you about rotating frames of reference, and centrifugal force? what do you know about them?

(i'm off to bed now :zzz:)
 
  • #17
I believe not , i don't even know which equation I should appy
 
  • #18
I believe not , I ont even know which equaton to apply.
it seems like w^2r is a possibility.
 
  • #19
(just got up :zzz:)

has your professor taught you about rotating frames of reference, and centrifugal force? what do you know about them?

2r and v2/r are the same, since v = ωr, even when ω isn't constant)
 

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