1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

I dont understand how to find the work done

  1. Oct 13, 2011 #1
    i dont understand how to find the "work" done

    A driver of a 7475 N car passes a sign stating "Bridge Out 25 Meters Ahead." She slams on the brakes, coming to a stop in 10 s. How much work must be done by the brakes on the car if it is to stop just in time? Neglect the weight of the driver, and assume that the negative acceleration of the car caused by the braking is constant.


    W=Fdcos



    i tried finding acceleration by doing 25=1/2a(10^2) = .125
    then finding mass by doing 7475=m(9.8)= 762.76
    and then Fnet = 762.76 x .125 = 95.35
    w= 95.35(25) = 2383.63
    ___________________________________________________

    i also tried finding Vf by using 25=1/2(0+Vf)10 = 1.25

    then i tried finding kinetic energy by 1/2(7475)(1.25^2)= 5839.84


    but neither of them are right so i have to be doing something wrong
     
    Last edited: Oct 13, 2011
  2. jcsd
  3. Oct 13, 2011 #2

    SammyS

    User Avatar
    Staff Emeritus
    Science Advisor
    Homework Helper
    Gold Member

    Re: i dont understand how to find the "work" done

    You had 25=1/2a(10^2) = .125 . ???


    I think you meant that a = .125, but that's wrong. Check your algebra.
     
  4. Oct 13, 2011 #3
    Re: i dont understand how to find the "work" done

    is it .5 rather?
     
  5. Oct 13, 2011 #4
    Re: i dont understand how to find the "work" done

    OH GOSH! i cant believe i made that dumb of a mistake! haha i got the right answer! thank you for correcting my algebra!
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook