I don't understand this simplification question for Power

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SUMMARY

The discussion focuses on the relationship between current, voltage, and power in electrical systems. It establishes that power (W) can be expressed in terms of current (A) and voltage (V) using the equations A = C/s and V = J•C^-1. The simplification leads to the conclusion that power is equivalent to J/s, which is defined as watts (W). Therefore, the units of power are confirmed to be watts, demonstrating a clear understanding of electrical unit conversions.

PREREQUISITES
  • Understanding of electrical units: current (A), voltage (V), and power (W).
  • Familiarity with the relationships between charge (C), energy (J), and time (s).
  • Basic knowledge of unit conversion in physics.
  • Ability to manipulate equations involving physical quantities.
NEXT STEPS
  • Research the derivation of electrical power formulas, including P = VI.
  • Study the implications of Ohm's Law on power calculations.
  • Explore the concept of energy efficiency in electrical systems.
  • Learn about the practical applications of watts in electrical engineering.
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This discussion is beneficial for students in physics or electrical engineering, educators teaching electrical concepts, and professionals seeking to reinforce their understanding of power calculations in electrical systems.

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Homework Statement


Given that the unit of current is related to the units of electric charge and time by A = C/s, and the unit of voltage is related to the units of energy and charge by V = J•C^-1, express the power in terms of these other units. Simplify the result further, given that the watt (W) is defined by W = J/s


Homework Equations


A = C/s
V = J•C^-1


The Attempt at a Solution


W = C/s • J•C^-1
W = J/s

Now what? I don't understand what the question is asking.
 
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They seem to be asking that since power is voltage times current, then it has units of J/s. Since a J/s is a watt, power has units of watts. You actually have the result.
 

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