I don't understand this step in turning this negative into a positive

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Homework Help Overview

The discussion revolves around understanding a step in simplifying a fraction involving negative values in the context of algebra. Participants are trying to clarify how a negative fraction can be converted into a positive one, specifically in the expression -2/(b-a) transitioning to 2/(a-b).

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the reasoning behind the conversion of negative fractions to positive ones, questioning the validity and necessity of such transformations. Some suggest that multiplying by -1/-1 is a method to achieve this, while others express uncertainty about the reasoning behind preferring positive numerators.

Discussion Status

The discussion is ongoing, with participants sharing their thoughts on the conversion process and its implications. Some have provided insights into the mathematical principles involved, while others are still seeking clarity on the rationale behind the approach taken in the original solution.

Contextual Notes

Participants note that there are no relevant equations provided, and the discussion is focused on the algebraic manipulation of fractions. There is an emphasis on the aesthetic preference for positive numerators in mathematical expressions.

Nathi ORea
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Homework Statement
I don't understand the final step of this working out
Relevant Equations
I don't think there is any.
So I have this question.
I get all the working out, but then I feel like the answer should be;
-2/(b-a).
Then I thought -2/(-a+b) must just be the same thing... all good so far..
Then they somehow just to 2/(a-b) as the final answer.. I'm lost there. How does that conversion happen?
Appreciate any help.
Screen Shot 2023-03-07 at 5.08.52 pm.png
 
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Nathi ORea said:
Then they somehow just to 2/(a-b) as the final answer.. I'm lost there. How does that conversion happen?
I believe they just multiplied by ##\frac{-1}{-1}## to get rid of the negative on top. Since ##\frac{-1}{-1}## is equal to ##1## you aren't changing the value of the fraction when you do so.
 
Nathi ORea said:
Homework Statement:: I don't understand the final step of this working out
Relevant Equations:: I don't think there is any.

So I have this question.
I get all the working out, but then I feel like the answer should be;
-2/(b-a).
Then I thought -2/(-a+b) must just be the same thing... all good so far..
Then they somehow just to 2/(a-b) as the final answer.. I'm lost there. How does that conversion happen?
Appreciate any help.View attachment 323312
That's a somewhat odd approach, IMO. I would have done:
$$\frac{1}{a-b} - \frac 1 {b-a} = \frac 1 {a -b} + \frac 1 {a -b} = \frac 2 {a-b}$$
 
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In the original solution, note that:
$$\frac{-X}{-Y} = \frac X Y$$For any expressions ##X## and ##Y##.
 
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Drakkith said:
I believe they just multiplied by ##\frac{-1}{-1}## to get rid of the negative on top. Since ##\frac{-1}{-1}## is equal to ##1## you aren't changing the value of the fraction when you do so.
Ok.. that’s what they did aye

Is there a reason why they did that?
 
Nathi ORea said:
Ok.. that’s what they did aye

Is there a reason why they did that?
Is it just neater to have a positive as the numerator or something?
 
Nathi ORea said:
Is it just neater to have a positive as the numerator or something?
It's because both the numerator and denominator were negative. It's much neater and easier to turn such fractions into positives. I'm sure you'd agree that ##\frac{-1}{-3}## is better to write as ##\frac{1}{3}## instead.
 

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