Calculus Problem: Blowing Up a Spherical Balloon

In summary, the conversation discusses a problem involving an expression that depends on a variable, while the given answer only provides a concrete number. The question asks why the assumption of constant dr/dt was made, and the answer explains that it is due to the constant volume flow rate. The conversation also mentions rearranging the expression to solve for dr/dt, which leads to the answer for part (b) and helps explain the behavior in part (c). Finally, the conversation suggests calculating dV/dr and using it to inform the answer.
  • #1
Idan9988
9
0
Homework Statement
.
Relevant Equations
.
IMG_20230527_195520.jpg

I'm struggling with section a. This is my calculation:
IMG20230527195328.jpg

The expression remains depend on the variable t, while in the answer is a concrete number:
Screenshot_2023-05-27-19-54-03-99_e2d5b3f32b79de1d45acd1fad96fbb0f.jpg
 
Physics news on Phys.org
  • #2
[itex]r = r_0 + 0.9t[/itex] is only valid if [itex]dr/dt[/itex] is constant.

Why did you assume that [itex]dr/dt[/itex] was constant? The question only tells you that [itex]dr/dt = 0.900\,\mathrm{cm}/\mathrm{s}[/itex] when [itex]r = 6.50\,\mathrm{cm}[/itex].
 
  • Like
Likes Idan9988, malawi_glenn and erobz
  • #3
Agree,

The answer (a) has all the information. Since the volume flow rate is constant, then ##\frac {dV}{dt}## is a constant.

##\frac {dr}{dt}## is variable.

If you rearrange the expression to solve for ##\frac {dr}{dt}## and you get the answer to (b) and the behavior that explains (c).
 
  • #4
Calculate ##\frac {dV} {dr}## and use this to inform your answer.
 

Similar threads

  • Introductory Physics Homework Help
Replies
25
Views
2K
  • Introductory Physics Homework Help
Replies
3
Views
1K
  • Introductory Physics Homework Help
Replies
14
Views
814
  • Introductory Physics Homework Help
Replies
3
Views
141
  • Introductory Physics Homework Help
Replies
28
Views
1K
  • Introductory Physics Homework Help
Replies
6
Views
1K
Replies
2
Views
742
  • Introductory Physics Homework Help
Replies
19
Views
1K
  • Introductory Physics Homework Help
Replies
3
Views
1K
  • Introductory Physics Homework Help
Replies
6
Views
2K
Back
Top