I have a big question(Dynamics-Parallel Velocities)

  • Thread starter Thread starter Queren Suriano
  • Start date Start date
  • Tags Tags
    kinematics
Click For Summary
SUMMARY

The discussion focuses on the conditions under which a bar can be considered in translation with an angular velocity of zero. It emphasizes that while the velocities at each point of the rod may be parallel when the angle is 0°, they do not necessarily share the same magnitude. A relative velocity analysis is essential to confirm that angular velocity is indeed zero, utilizing the equation Vab = Va + Vb/a. The simplification shows that for angular velocity to exist, the components of velocity must be analyzed correctly.

PREREQUISITES
  • Understanding of relative velocity analysis
  • Familiarity with angular velocity concepts
  • Knowledge of vector components in physics
  • Basic principles of rigid body motion
NEXT STEPS
  • Study relative velocity analysis in rigid body dynamics
  • Learn about angular velocity and its implications in motion
  • Explore vector decomposition and its applications in physics
  • Investigate the principles of translational versus rotational motion
USEFUL FOR

Students and professionals in physics, mechanical engineering, and robotics who are analyzing motion dynamics and the relationship between translational and rotational velocities.

Queren Suriano
Messages
48
Reaction score
0
In this problem why it is not considered that the bar is in translation (angular velocity = 0) if at the time when the angle is 0 °, the velocities at each point of the rod are parallel??
upload_2014-11-21_18-1-41.png
 
Engineering news on Phys.org
They might be parallel, but they don't necessarily have the same magnitude.
 
  • Like
Likes   Reactions: Queren Suriano
Your comment made me realize that to affirm that the angular velocity is zero, must be checked with a relative velocity analysis, in this case Vab = Va + V b / a; (Vab) x (i) + (Vab) y (j) = Va (i) + [w (k) x (L / 2 (j))] where simplification is that (Vab) y = 0; (Vab) x = Va + (wL / 2); where it exists angular velocity.

Thank You!
 

Similar threads

  • · Replies 62 ·
3
Replies
62
Views
6K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 13 ·
Replies
13
Views
3K
  • · Replies 0 ·
Replies
0
Views
788
Replies
2
Views
1K
  • · Replies 19 ·
Replies
19
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
0
Views
3K