MHB I made 2 equations but can they become 1

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The discussion revolves around combining two equations to simplify a CNC machine operation. The first equation, which uses arcsine, calculates an angle based on the chord and radius, while the second equation uses that angle to compute the necessary input for the machine. By substituting the first equation into the second, a single equation is formed: y = r*sin(0.5*arcsin(C/r)). This simplification allows for easier calculations on a calculator. The user expresses gratitude for the assistance in streamlining the process.
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So a little background then to the point, I needed to get a cnc machine to do something it don’t want to do, so I came up with 2 equations to lie to the machine to get it to do an operation correctly. It is a radius equation that finds the center point of a radius if it is not a full radius. Can these be combined to make one?

1st: Asin(chord/radius)=x
2nd: radius[sin(x/2)]=y

Y is the input for the machine, it’s the important answer.
 
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Welcome, DRMSquared! (Wave)

DRMSquared said:
Can these be combined to make one?

1st: Asin(chord/radius)=x
2nd: radius[sin(x/2)]=y

Y is the input for the machine, it’s the important answer.
In the first equation, does Asin mean the Arcsine, or does it mean $A$ times sin where $A$ is some constant?
 
Euge said:
Welcome, DRMSquared! (Wave)

In the first equation, does Asin mean the Arcsine, or does it mean $A$ times sin where $A$ is some constant?

It would be sin-1 so I’m guessing arcsine
 
Ok. For simplicity, let $C = \text{chord}$ and $r = \text{radius}$. Equation 1 is then $x = \arcsin(C/r)$. Plugging in the expression of $x$ into Equation 2 yields $$y = r\sin(.5\arcsin(C/r))$$
 
Euge said:
Ok. For simplicity, let $C = \text{chord}$ and $r = \text{radius}$. Equation 1 is then $x = \arcsin(C/r)$. Plugging in the expression of $x$ into Equation 2 yields $$y = r\sin(.5\arcsin(C/r))$$

You my friend are awesome, thank you so much, now I can easily plug this into my hp48g and have an easier and quicker time doing this problem.
 
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