I need help making a relation between piezoelectricity and earthquake

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The discussion focuses on formulating an equation that connects piezoelectricity with seismic waves generated by earthquakes. The user is exploring how to calculate stress and strain on a piezoelectric system based on earthquake energy, using magnitude and distance attenuation. They confirm that this inquiry is for schoolwork and have approached it logically so far. Other participants suggest utilizing scientific articles for a more robust understanding of the topic, recommending resources like Google Scholar. The conversation emphasizes the importance of grounding the approach in established research.
SiddSha
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TL;DR Summary: Tasked to formulate an equation relating piezoelectric effect and seismic waves during earthquakes. Using magnitude and distance attenuation to calculate stress/strain on the piezo system from earthquake energy. Need help checking if the basis and idea are correct

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Is this for schoolwork? What resources have you been reading to try to come up with this?
 
Yes it is, so far I have only done it in a purely logical manner
 
SiddSha said:
Yes it is
Okay, I'll move your thread to the schoolwork forums then.

SiddSha said:
so far I have only done it in a purely logical manner
That's probably not the best way to approach this. Try searching for scientific articles on the subject to see how others have approached the problem. You could do the search with Google Scholar to narrow the results to scientific articles.
 
Thread 'Chain falling out of a horizontal tube onto a table'
My attempt: Initial total M.E = PE of hanging part + PE of part of chain in the tube. I've considered the table as to be at zero of PE. PE of hanging part = ##\frac{1}{2} \frac{m}{l}gh^{2}##. PE of part in the tube = ##\frac{m}{l}(l - h)gh##. Final ME = ##\frac{1}{2}\frac{m}{l}gh^{2}## + ##\frac{1}{2}\frac{m}{l}hv^{2}##. Since Initial ME = Final ME. Therefore, ##\frac{1}{2}\frac{m}{l}hv^{2}## = ##\frac{m}{l}(l-h)gh##. Solving this gives: ## v = \sqrt{2g(l-h)}##. But the answer in the book...

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