(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

2 kg uniform rod of length 1m is constrained to rotate about a horizontal axis passing through its center. The rod has a 1.5 kg point mass attached to one end and a 0.5 kg point mass attached to the other end. The 1.5 kg mass is given a downward push so that it starts moving with an initial velocity of 1.2 m/s.

Ok I used the equation of moment of inertia or rotational inertia

I=m(r)^2

Here's what I did

m1=.5 kg

m2=1.5 kg

M=2kg

r=1/2 because L =1m and the center of mass is in the middle of the rod

thus I plugged in the variable

I=.5(1/2)^2 +1.5(1/2)^2

=.5 kg*m^2

is that right

and next i have to find the initial kinetic energy and then i have to find the total angle of it coming to rest. I need help

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# Homework Help: I need to to find the moment of inertia for the system

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