I solved 2 simple question but i need to make sure help please?

[wmsaqqa]

1)- A person lifts a mass of 20.0 kg vertically upwards at a constant speed of 0.200 m/s through a distance of 0.800 m. What is the work done by the person?

A) 156.8 J
B) 3.20 J
C) 16.0 J
D) None of the other choices is correct.

I choosed the answer B.
I used the law : W = F x D = (20 x 0.2) x 0.8 = 3.2
Am i correct?

________________________________________________________

2)- A truck is towing a car whose mass is one quarter that of the truck. The force exerted by the truck on the car is 6000 N. The force exerted by the car on the truck is

A) 6000 N.
B) 24000 N.
C) 3000 N.
D) 1500 N.

I choosed the answer D, because the the force exerted by the truck on the car is 6000 N, and the car's mass is one quarter that of the truck, so 6000/4 = 1500 N.
Am i correct?_________________________________________________________

And for this question.. i only need to know the law..

A 40.0-kg crate is being lowered by means of a rope. Its downward acceleration is 2.00 m/(s)2 . What is the force exerted by the rope on the crate?

A) 312 N.
B) 40.0 N.
C) 472 N.
D) 232 N.

 

[briantaekim]

Check out the PDF attachment below!

 

[NascentOxygen]

1)- A person lifts a mass of 20.0 kg vertically upwards at a constant speed of 0.200 m/s through a distance of 0.800 m. What is the work done by the person?

A) 156.8 J
B) 3.20 J
C) 16.0 J
D) None of the other choices is correct.

I choosed the answer B.
I used the law : W = F x D

No you didn't. You should have, but you didn't.

You calculated F as being equal to 20 x 0.2
but there is no formula in physics that says force = mass x speed

Think about it some more.

2)- A truck is towing a car whose mass is one quarter that of the truck. The force exerted by the truck on the car is 6000 N. The force exerted by the car on the truck is

A) 6000 N.
B) 24000 N.
C) 3000 N.
D) 1500 N.

I choosed the answer D

Not correct.

Hint: to every action there is an equal and opposite reaction

And for this question.. i only need to know the law..

A 40.0-kg crate is being lowered by means of a rope. Its downward acceleration is 2.00 m/(s)2 . What is the force exerted by the rope on the crate?

A) 312 N.
B) 40.0 N.
C) 472 N.
D) 232 N.

The question involves a mass and its acceleration, so
the law that should spring to mind is F = ma
but you'll need to draw a diagram of the forces so you can clearly see what is going on.

 

[cupid.callin]

1)- A person lifts a mass of 20.0 kg vertically upwards at a constant speed of 0.200 m/s through a distance of 0.800 m. What is the work done by the person?

A) 156.8 J
B) 3.20 J
C) 16.0 J
D) None of the other choices is correct.

I choosed the answer B.
I used the law : W = F x D = (20 x 0.2) x 0.8 = 3.2
Am i correct?

How about the formula: Change in kinetic energy = total work done on body ?

 

[mtayab1994]

The work of weight is special its: m*g*h
you have 20kgs and g is a constant and you have h so you should be able to easily solve it.

 

[wmsaqqa]

Thank you guys.. i solved them all.. all of them the answer is A.. right?

 

[mtayab1994]

Thank you guys.. i solved them all.. all of them the answer is A.. right?

Yep that's what it looks like to me

 

[wmsaqqa]

A 40.0-kg crate is being lowered by means of a rope. Its downward acceleration is 2.00 m/(s)2 . What is the force exerted by the rope on the crate?

A) 312 N.
B) 40.0 N.
C) 472 N.
D) 232 N.

for this question.. i solved it by using this law

mg - T = F

(40 - 9.8) - T = (40 x 2)

392 - T = 80

392 - 80 = T

312 = T

Correct ??

 

[cupid.callin]

for this question.. i solved it by using this law

mg - T = F

(40 - 9.8) - T = (40 x 2)

392 - T = 80

392 - 80 = T

312 = T

Correct ??

yepp

 

[NascentOxygen]

How about the formula: Change in kinetic energy = total work done on body ?

There certainly is such a formula. What answer would it give you here?

 

[cupid.callin]

There certainly is such a formula. What answer would it give you here?

Change in kinetic energy is 0. and only work done is by gravity and man

so -(work by gravity) = work by man ...