I think it's my ignorance of not accepting that I can't do it, because

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The discussion centers on solving the equation \(\frac{\pi}{n+1} = \cos^{-1}\left(\frac{1-m}{\sqrt{1+m^2}}\right) + \frac{(m-1)\sqrt{2m}}{1+m^2}\) for the variable \(m\). The user expresses doubt about the solvability of the equation but seeks methods to find a numerical value for \(m\) given a specific \(n\). The equation can be simplified to \(\frac{2\pi}{n+1} = \alpha - \sin\alpha\), where \(\cos\frac{\alpha}{2} = \sqrt{\frac{2m}{1+m^2}}\). Numerical methods are suggested for finding \(m\) when analytical solutions are not feasible.

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I think it's my ignorance of not accepting that I can't do it, because I'm almost certain that it cannot be done, yet I'm still asking.

Anyway, can this equation be solved for m?

[tex]\frac{\pi}{n+1}=cos^{-1}\left(\frac{1-m}{\sqrt{1+m^2}}\right)+\frac{(m-1)\sqrt{2m}}{1+m^2}[/tex]

If it cannot be done (which I'm almost certain will be the case), for a given n, how can I still find the value for m? Be it a numerical value if it must...
 
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The equation can be simplified to
[tex] \frac{2\pi}{n+1}=\alpha-\sin\alpha[/tex]
where
[tex] \cos\frac{\alpha}{2}=\sqrt{\frac{2m}{1+m^2}}[/tex]
and then has to be solved numerically.

Please check if I didn't do a mistake.
 
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