# I want to know if I got this question right on my physics test

## Homework Statement

A shuttle is in orbit 400km above the Earths surface, and circles it every 90 minutes. Find the centrip. acceleration and find it in terms of g. (He says for sake of ease, assume gravity = 10 m/s^2)

## Homework Equations

$$a_{c}=\frac{v^2}{r}, v=\frac{2{\pi}r}{t}$$

## The Attempt at a Solution

First I converted everything to meters and seconds:

6400 km = 6400000m, 90 minutes = 5400 seconds

$$v=\frac{2{\pi}r}{t}$$
$$v=\frac{2{\pi}(6400000+400000)}{5400}$$
$$v=7900\frac{m}{s}$$

$$a_{c}=\frac{v^2}{r}$$
$$a_{c}=\frac{7900^2}{6800000}$$
$$a_{c}=\frac{6.3{\cdot}10^7}{6800000}$$
$$a_{c}=9.2\frac{m}{s^2}$$

= .92g's

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