I with some Equilibrium problems

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Homework Help Overview

The discussion revolves around a problem involving equilibrium, specifically focusing on a traffic light suspended from a pole. Participants are tasked with determining the tension in a cable and the forces exerted by a pivot point.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the weights of the pole and the traffic light, and the angles involved. There is an exploration of the concept of torque and the conditions for equilibrium, particularly the sum of torques being zero. Questions arise regarding the assumptions about forces and their directions.

Discussion Status

Some participants have provided insights on how to approach the problem, suggesting methods such as taking moments about the pivot point. There is an ongoing exploration of terminology and concepts related to torque and equilibrium.

Contextual Notes

There is mention of specific values for weights and angles, as well as a reference to a figure that is not included in the discussion. Participants also note variations in terminology that may affect understanding.

SalamanderGod
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#2: A traffic light hangs from a structure as shown in Fig. 9-60. The uniform aluminum pole AB is 7.5 m long and has a mass of 8.0 kg. The mass of the traffic light is 12.0 kg. Determine the tension in the horizontal massless cable CD, and the vertical and horizontal components of the force exerted by the pivot A on the aluminum pole.
http://img457.imageshack.us/my.php?image=fig960xg6.png

Can I just get help on this one? I figured out the rest.
 
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Anyone want to help?
 
One is expected to show ones efforts. Let's start with what you know...
 
Well, I know that the weight of the pole is 78.4 N and the light's weight is 117.6N, and that the light makes a 53degree angle with the pole, and since the sum of torques has to be 0, I need to separate the weights into their x and y components... the problem with that was I got stuck when I realized that I didn't know what the x value of the point Ft acts on was... Is it safe to assume that since sum of torques is 0, that Ft and the force exerted by A are aqual but opposite in direction?
 
I would recommend taking moments about point A, then you don't need to worry about any forces acting through A. :wink:
 
"taking moments"? do you mean setting A as the origin for torque?
 
SalamanderGod said:
"taking moments"? do you mean setting A as the origin for torque?
Yes, apologies; the jargon can vary from course to course.
 
ok, thanks!
 

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