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Identical bosons vs. fermions in square potential well

  1. Dec 18, 2008 #1
    The following Wolfram web page shows the probability density functions for two identical bosons in a square potential well. It also shows the probability density for two identical fermions.


    So it appears that each is just a 90 degree rotation of the other. That doesn't seem correct. If Bosons can share the same state, shouldn't their lowest state just be a single blob in the middle (per the ground state for a single particle)? I know that quantum mechanics is very non-intuitive, so I'm probably missing something. Please help to explain this. Thank you.

  2. jcsd
  3. Dec 18, 2008 #2


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    The sliders at the top tell you the individual states. The starting point is one particle in the ground state (n=1) and one in the first excited state (n=2). For fermions, antisymmetrizing these does give the ground state, but for bosons, you would need n=1 for both, which would give a single blob in the middle.
  4. Dec 18, 2008 #3
    Ah I see. Thank you.
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