Identifying the slope of a line

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Homework Help Overview

The discussion revolves around identifying the slope of a line using two points. Participants are examining the accuracy of chosen points and the application of the slope formula.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the selection of points (8,-3) and (-6,4) and their application in the slope formula. Questions arise about the correctness of the calculations and the representation of the slope.

Discussion Status

Some participants provide tips on notation and clarify the formula's structure. There is acknowledgment of different representations of the slope, but no consensus on the accuracy of the points or calculations has been reached.

Contextual Notes

Participants express confusion regarding the accuracy of their chosen points and the resulting slope, indicating a potential misunderstanding of the slope formula or the points' validity.

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Homework Statement


identifying the slope of the line?[/B]
upload_2016-4-20_12-45-28.png


Homework Equations


y2-y1/x2-x1

The Attempt at a Solution


i chose two points on the line, the first point is (8,-3) and the second point is (-6,4). Are these points accurate?
i used the slope equation to solve for the slope of the line from the graph:
4-(-3) / -6-8 = -7/14 = -1/2

is this right?
 
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Well done. One tip: use brackets -- not 4-(-3) / -6-8 but ( 4-(-3) ) / ( -6-8 )
 
can the answer also be 7/-14 and 1/-2
 
Kirito123 said:

Homework Statement


identifying the slope of the line?[/B]
View attachment 99414

Homework Equations


y2-y1/x2-x1

The Attempt at a Solution


i chose two points on the line, the first point is (8,-3) and the second point is (-6,4). Are these points accurate?
i used the slope equation to solve for the slope of the line from the graph:
4-(-3) / -6-8 = -7/14 = -1/2

is this right?



What you wrote means ##y_2 - \frac{y_1}{x_2} - x_2##, which is not correct. Did you mean ##\frac{y_2 - y_1}{x_2 - x_1}##? If so, you need to use parentheses, like this: (y2-y1)/(x2-x1).
 
Both of these are the same value as ##-{1\over 2}##, which is the simplest way to express that value. Whatever points you choose, you always get ## - {a\over 2a}## as a result.
 
got it, thanks!
 
Kirito123 said:
i chose two points on the line, the first point is (8,-3) and the second point is (-6,4). Are these points accurate?
i used the slope equation to solve for the slope of the line from the graph:
4-(-3) / -6-8 = -7/14 = -1/2

is this right?

its a straight line ,so where lies the confusion about its being wrong?
 
i solved this question previously and got a different slope compared to what I'm getting now. Then i realized that my points were wrong when doing it the first time, so i wanted to make sure the points i chose were correct in my second attempt.
 
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