Question: Determine the equation of a line for the following: a) The line that has an x-intercept of 6 and that passes through the point (2, –2) b)The line that never intersects 5x – y + 3 = 0, and which is five grid squares lower than that line Relevant equation: y= mx+b Attempt at a solution: for a, I know that the x intercept is +6, and the line has to pass through the points (2, -2). Does this mean i have to graph the line first, then solve for the slope of the line (m) and use any point on the line (x,y) to solve for b once i solve for the slope: After graphing the line i found the slope 2/4 or 1/2. I had to find b so i put the values i got in standard form: 2=1/2(-2) + b I simplified both sides of the equation. 2=1/2(−2)+b Simplify: 2=b−1 I then flip the equation. b−1=2 I added 1 to both sides. b−1+1=2+1 b=3 My answer: b=3 Is that the correct way to do it?? for b, i solved for the slope intercept form of the line, then i graphed it, and counted five grid squares down. Then, i calculated the slope and y-intercept of the new line: 5x – y + 3 = 0 5x –y = -3 –y = -5x -3 y = -5x -3 /-1 y = 5x + 3 after graphing this line, i counted 5 square grids down and got new line that has a y-intercept of -2, and the same slope as the original line (+5) so the equation of the line for part b is: y=5x -2 is this correct???