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Question:

Determine the equation of a line for the following:

a) The line that has an

b)The line that never intersects 5

Relevant equation:

y= mx+b

Attempt at a solution:

for a, I know that the x intercept is +6, and the line has to pass through the points (2, -2). Does this mean i have to graph the line first, then solve for the slope of the line (m) and use any point on the line (x,y) to solve for b once i solve for the slope:

After graphing the line i found the slope 2/4 or 1/2. I had to find b so i put the values i got in standard form:

2=1/2(-2) + b

I simplified both sides of the equation.

2=1/2(−2)+b

Simplify: 2=b−1

I then flip the equation.

b−1=2

I added 1 to both sides.

b−1+1=2+1

b=3

b=3

Is that the correct way to do it??

for b, i solved for the slope intercept form of the line, then i graphed it, and counted five grid squares down. Then, i calculated the slope and y-intercept of the new line:

5

5

–

y = -5x -3 /-1

y = 5x + 3

after graphing this line, i counted 5 square grids down and got new line that has a y-intercept of -2, and the same slope as the original line (+5)

so the equation of the line for part b is:

y=5x -2

is this correct???

Determine the equation of a line for the following:

a) The line that has an

*x*-intercept of 6 and that passes through the point (2, –2)b)The line that never intersects 5

*x*–*y*+ 3 = 0, and which is five grid squares lower than that lineRelevant equation:

y= mx+b

Attempt at a solution:

for a, I know that the x intercept is +6, and the line has to pass through the points (2, -2). Does this mean i have to graph the line first, then solve for the slope of the line (m) and use any point on the line (x,y) to solve for b once i solve for the slope:

After graphing the line i found the slope 2/4 or 1/2. I had to find b so i put the values i got in standard form:

2=1/2(-2) + b

I simplified both sides of the equation.

2=1/2(−2)+b

Simplify: 2=b−1

I then flip the equation.

b−1=2

I added 1 to both sides.

b−1+1=2+1

b=3

__My answer:__b=3

Is that the correct way to do it??

for b, i solved for the slope intercept form of the line, then i graphed it, and counted five grid squares down. Then, i calculated the slope and y-intercept of the new line:

5

*x*–*y*+ 3 = 05

*x*–*y*= -3–

*y*= -5x -3y = -5x -3 /-1

y = 5x + 3

after graphing this line, i counted 5 square grids down and got new line that has a y-intercept of -2, and the same slope as the original line (+5)

so the equation of the line for part b is:

y=5x -2

is this correct???