MHB If 1m^2 price is 9.33 $ then what's the price for 1meter?

[nominj98]

If 1m^2 price is 9.33 $ then what's the price for 1meter?
-----------------------------------------------------------
1m^2 = 9.33 $
1m = ?

 

[skeeter]

cannot be determined because it doesn't make sense ...

$m^2$ is a two-dimensional area; $m$ is one-dimensional length

you can pay \$9.33 for a square meter of carpet, but you can't buy 1 meter of carpet

 

[nominj98]

Ohh sorry for my mistake, I forgot to add this picture, Please help me to answer this.
If 1m^2 price is 9.33 $ then what's the price for 1meter?
-----------------------------------------------------------
1m^2 = 9.33 $
1m = ?

 

[HOI]

Having been told that a carpet, which covers and area, must be measured in an area measure, like $m^2$, so that you can't buy "1 m" of carpet, and your question is meaningless, why do you ask exactly the same question again?

You have included a picture now, but with no explanation. What is this picture of and what does it have to do with carpets?

 

[nominj98]

There is nothing to do with any carpet, This tube which is in this picture has to be coloured, The price for colouring this tube is 1m^2 = 9.33$, I need to find the price for 1m, I know what you mean about "m^2 is a two-dimensional area; m is one-dimensional length", The reason I keep asking is that one guy keeps on asking this answer and I don't know how to get this, this is how I answered but he is telling it is wrong and not giving me the answer, Please help me if you can.

 

[skeeter]

circumference of a circle = $2\pi$ times the radius, or $\pi$ times the diameter

you seem to want the surface area of a hollow tube one meter in length with an approximate diameter of 50.55 units, which I'm assuming are millimeters ... note your cross-section is close to be circular, but is actually an ellipse.

$A = C \cdot L = \pi \cdot d \cdot L \approx \pi \cdot (0.055 \, m) \cdot (1 \, m) \approx 0.173 \, m^2$

based on that area ...

$\dfrac{\$ 9.33}{1 \, m^2} = \dfrac{\$ x}{0.173 \, m^2} \implies x \approx \$1.61$