If 3d is higher in energy than 4S, how is 4s ionised first?

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The discussion addresses the ionization of the 4s orbital before the 3d orbital, despite the latter being higher in energy. It clarifies that the ionization process can remove electrons from any orbital with sufficient energy, leading to shifts in energy levels for remaining electrons. Furthermore, it explains that noble gases like argon are considered to have a full outer shell due to the complete filling of their s and p orbitals, even when the 3d orbital remains empty.

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just as the title says, how is 4s ionised first if 3d is higher in energy? also, how does argon have a full outershell if its 3d is empty?
 
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Ionized first by which process? You can kick out every electron with sufficient energy. In addition, removing an electron will shift the energy levels for the other electrons.

"Full" in the context of noble gases refers to the s and p orbitals.
 

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