- #1
a_skier
- 17
- 0
Homework Statement
Prove: if a[itex]\neq[/itex]0 then b/a=b*a^-1
I don't know if my proof is sufficient with this one but I cannot think of another way. Also I am only supposed to use the basic axioms (e.g. commutative, distributive, existence of reciprocal...)
Homework Equations
1/a=a^-1 (I am not supposed to use this)
Distributive law
The Attempt at a Solution
b/a=b*(1/a)
=b*(a^-1)
=b*a^-1
I am not allowed to use the (1/a)=a^-1 thing, but I can't think of how to tackle this one any other way. Could someone at least get me pointed in the right direction? I am confused because the property seems too obvious hahaha.